Question

A torque of 12 N*m is applied to a solid uniform disk of radius 0.50 m. If the disk accelerates at 2.6 rad/s^2 what is the mass of the disk? A) 26 kg B) 25kg C) 17 kg D) 34 kg

Answer 1

Answer:

mass = 36.92 kg

Explanation:

We have given the torque $\tau =12 N-m$

Radius of the disk r = 0.50 m

Angular acceleration $\alpha =2.6rad/sec^2$

We know that torque is given by $\tau =I\alpha$ here I is moment of inertia and $\alpha$ is angular acceleration

So $12=I\times 2.6$

$I=\frac{12}{2.6}=4.6153kgm^2$

Moment of inertia is given by $I=\frac{1}{2}mr^2$

$4.6153=\frac{1}{2}m0.5^2$

m = 36.92 kg

The given answer is not matched with this answer but after calculation i got m =36.92 kg