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Setler [38]
3 years ago
7

What do we call the minimum energy that is required by an electron to leave the metal target in the photoelectric effect?Select

one of the options below as your answer: A. energy function B. minimum function C. work function D. quanta E. electrical energy
Physics
2 answers:
Liula [17]3 years ago
7 0

Answer:

C. work function

Explanation:

In the photoelectric effect, the energy of the incident photon is used in part to extract the electron from the metal (and this energy is called work function) and the rest is converted into kinetic energy of the electron. In formula:

hf = \phi +K

where

hf is the energy of the incident photon, which is the product between h (the Planck constant) and f (the photon's frequency)

\phi is the work function

K is the kinetic energy of the photoelectron as it leaves the material

Sergio [31]3 years ago
6 0
The work function is what we call the minimum energy that is required by an electron to leave the metal target in the photoelectric effect. 
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Answer:

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The length of a 100 mm bar of metal increases by 0.3 mm when subjected to a temperature rise of 100°C. The coefficient of linear
Juli2301 [7.4K]

Answer:

α = 3×10^-5 K^-1

Explanation:

let ΔL be the change in length of the bar of metal, ΔT be the change in temperature, L be the original length of the metal bar and let α be the coefficient of linear expansion.

then, the coefficient of linear expansion is given by:

α = ΔL/(ΔT×L)

   = (0.3×10^-3)/(100)(100×10^-3)

   = 3×10^-5 K^-1

Therefore, the coefficient of linear expansion is 3×10^-5 K^-1

5 0
3 years ago
10. How much total work do you do when you lift a 50 kg microwave 1.0 m off the ground and then push it 1.0 m
Mariulka [41]

Work formula:

W = Fd\cos(\theta)

F = 50N, d = 1.0 m

When you lift something straight up, the angle of the force is 90º

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W = (50N)(1.0)(0) = 0

F = 50N, d = 1.0 m

When you push the microwave, the angle is 0º and cos(0º) is 1. So there is work done here:

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6 0
2 years ago
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bija089 [108]

This question is incomplete, the complete question is;

Scientists studying an anomalous magnetic field find that it is inducing a circular electric field in a plane perpendicular to the magnetic field. The electric field strength 1.5 m from the center of the circle is 7 mV/m.

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Answer:

the magnetic field changing at the rate of 9.33 m T/s

Explanation:

Given the data in the question;

Electric field E = 7 mV/m

radius r = 1.5 m

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∫E.dl = d∅/dt

E∫dl = A( dB/dt )

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( 0.007 ) = 0.75 ( dB/dt )

dB/dt = 0.007 / 0.75

dB/dt = 0.00933 T/s

dB/dt = ( 0.00933 × 1000) m T/s

dB/dt = 9.33 m T/s

Therefore, the magnetic field changing at the rate of 9.33 m T/s

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shtirl [24]

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