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Setler [38]
3 years ago
7

What do we call the minimum energy that is required by an electron to leave the metal target in the photoelectric effect?Select

one of the options below as your answer: A. energy function B. minimum function C. work function D. quanta E. electrical energy
Physics
2 answers:
Liula [17]3 years ago
7 0

Answer:

C. work function

Explanation:

In the photoelectric effect, the energy of the incident photon is used in part to extract the electron from the metal (and this energy is called work function) and the rest is converted into kinetic energy of the electron. In formula:

hf = \phi +K

where

hf is the energy of the incident photon, which is the product between h (the Planck constant) and f (the photon's frequency)

\phi is the work function

K is the kinetic energy of the photoelectron as it leaves the material

Sergio [31]3 years ago
6 0
The work function is what we call the minimum energy that is required by an electron to leave the metal target in the photoelectric effect. 
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Suppose light from a 632.8 nm helium-neon laser shines through a diffraction grating ruled at 520 lines/mm. How many bright line
Leya [2.2K]

Answer:

1 bright fringe every 33 cm.

Explanation:

The formula to calculate the position of the m-th order brigh line (constructive interference) produced by diffraction of light through a diffraction grating is:

y=\frac{m\lambda D}{d}

where

m is the order of the maximum

\lambda is the wavelength of the light

D is the distance of the screen

d is the separation between two adjacent slit

Here we have:

\lambda=632.8 nm = 632.8\cdot 10^{-9} m is the wavelength of the light

D = 1 m is the distance of the screen (not given in the problem, so we assume it to be 1 meter)

n=520 lines/mm is the number of lines per mm, so the spacing between two lines is

d=\frac{1}{n}=\frac{1}{520}=1.92\cdot 10^{-3} mm = 1.92\cdot 10^{-6} m

Therefore, substituting m = 1, we find:

y=\frac{(632.8\cdot 10^{-9})(1)}{1.92\cdot 10^{-6}}=0.330 m

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6 0
3 years ago
two ships leave a port at the same time. The first ship sails on a bearing of 40 degrees at 18 knots and the second at a bearing
Yuliya22 [10]

Answer:

The distance between the ships is 87.84 km.

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Given that,

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Using cosine rule

v=\sqrt{v_{1}^2+v_{2}^2-2v_{1}v_{2}\cos\theta}

Put the value into the formula

v=\sqrt{18^2+26^2-2\times18\times26\times\cos90}

v=\sqrt{18^2+26^2}

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d =v\times t

Put the value into the formula

d=10\sqrt{10}\times1.5\times1.852

d=87.84\ km

Hence, The distance between the ships is 87.84 km.

7 0
3 years ago
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