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Setler [38]
3 years ago
7

What do we call the minimum energy that is required by an electron to leave the metal target in the photoelectric effect?Select

one of the options below as your answer: A. energy function B. minimum function C. work function D. quanta E. electrical energy
Physics
2 answers:
Liula [17]3 years ago
7 0

Answer:

C. work function

Explanation:

In the photoelectric effect, the energy of the incident photon is used in part to extract the electron from the metal (and this energy is called work function) and the rest is converted into kinetic energy of the electron. In formula:

hf = \phi +K

where

hf is the energy of the incident photon, which is the product between h (the Planck constant) and f (the photon's frequency)

\phi is the work function

K is the kinetic energy of the photoelectron as it leaves the material

Sergio [31]3 years ago
6 0
The work function is what we call the minimum energy that is required by an electron to leave the metal target in the photoelectric effect. 
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Properties such as luster conductivity and flexibility are used to describe what type of elements
pickupchik [31]
Answer: metals.

Justification:

There are 118  elements which you can find in the periodic table ordered by atomic number. Those elements my be classified into metals, non-metals and metalloids.

The metals are placed on the left side of the periodic table. The metals share the properties of luster, conductivity and flexibility.

The properties of non-metals (which are on the right side of the periodic table) are opposite to those of metals: opaque, low conductivity and brittle.

Metalloids have in between properties.

Copper, for example is a metal: it has luster, is flexible and is highly conductive of the electricity (and temperature).


4 0
3 years ago
which statement is a Hypothesis? A: Most of the earthworms moved to the shaded area during experiment. B: If an earthworm is giv
True [87]

Answer:

B

Explanation:

It's saying what you think

3 0
3 years ago
A rocket initially at rest accelerates at a rate of 99. 0 meters/second2. Calculate the distance covered by the rocket if it att
creativ13 [48]

The rocket will cover 1 \times  10^3\rm \ m distance in 4. 5 s. Acceleration can be defined as the change in velocity.

<h3>What is acceleration?</h3>

Acceleration can be defined as the change in speed or the direction of the object.

From kinamatic equation:

D = v_{t} +\dfrac 12at^2

Where,

D - final velocity =  445 m/s

v_0 -  initial valocity = 0 m/s

a - acceleration = 99. 0 m/s²

t - time =  4. 50 s

Put the values in the formula,

D = 0\times  ( 4.5) + \dfrac12\times (99)(4.5)^2\\\\D = 1002 {\rm \ m}\\\\D = 1 \times  10^3\rm \ m

Therefore, the rocket will cover 1 \times  10^3\rm \ m distance in 4. 5 s.

Learn more about Acceleration :

brainly.com/question/2697545

7 0
3 years ago
The amount of light lost within a fiber-optic system is known as
densk [106]
Attenuation is the correct answer. 
6 0
3 years ago
A rock is thrown off a 50.0 m high cliff. How fast must the rock leave the cliff top to land on level ground below, 90 m from th
blagie [28]

Answer:

The rock must leave the cliff at a velocity of 28.2 m/s

Explanation:

The position vector of the rock at a time t can be calculated using the following equation:

r = (x0 + v0x · t, y0 + 1/2 · g · t²)

Where:

r = position vector at time t.

x0 = initial horizontal position.

v0x = initial horizontal velocity.

t = time.

g = acceleration due to gravity (-9.81 m/s² considering the upward direction as positive).

Please, see the attached figure for a graphical description of the problem. Notice that the origin of the frame of reference is located at the edge of the cliff so that x0 and y0 = 0.

When the rock reaches the ground, the position vector will be (see r1 in the figure):

r1 = (90 m, -50 m)

Then, using the equation of the vector position written above:

90 m = x0 + v0x · t

-50 m = y0 + 1/2 · g · t²

Since x0 and y0 = 0:

90 m = v0x · t

-50 m = 1/2 · g · t²

Let´s use the equation of the y-component of the vector r1 to find the time it takes the rock to reach the ground and with that time we can calculate v0x:

-50 m = 1/2 · g · t²

-50 m = -1/2 · 9.81 m/s² · t²

-50 m / -1/2 · 9.81 m/s² = t²

t = 3.19 s

Now, using the equation of the x-component of r1:

90 m = v0x · t

90 m = v0x · 3.19 s

v0x = 90 m / 3.19 s

v0x = 28.2 m/s

8 0
3 years ago
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