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Anna [14]
3 years ago
9

Properties such as luster conductivity and flexibility are used to describe what type of elements

Physics
1 answer:
pickupchik [31]3 years ago
4 0
Answer: metals.

Justification:

There are 118  elements which you can find in the periodic table ordered by atomic number. Those elements my be classified into metals, non-metals and metalloids.

The metals are placed on the left side of the periodic table. The metals share the properties of luster, conductivity and flexibility.

The properties of non-metals (which are on the right side of the periodic table) are opposite to those of metals: opaque, low conductivity and brittle.

Metalloids have in between properties.

Copper, for example is a metal: it has luster, is flexible and is highly conductive of the electricity (and temperature).


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An ideal gas is enclosed in a piston, and 1600 J of work is done on the gas. As this happens, the internal energy of the gas inc
Phantasy [73]

Answer:

- 1100 J heat flows out

Explanation:

dW = - 1600 J (as work is done on the gas)

dU = 500 J

dQ = ?

According to the first law of thermodynamics

dQ = dU + dW

dQ = 500 - 1600

dQ = - 1100 J

As heat is negative so it flows out.

3 0
3 years ago
A concave (convergent) mirror has a focus of 3.4 cm. A tree that is 0.5cm tall is situated 4.5 cm away from the mirror. Calculat
Elanso [62]

The image position is 13.9 cm from the mirror

Explanation:

To solve this problem, we can use the mirror equation:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where

f is the focal length

p is the distance of the object from the mirror

q is the distance of the image from the mirror

In this problem, we have:

f = 3.4 cm is the focal length of the mirror (positive for a concave mirror)

p = 4.5 cm is the position of the object (the tree)

Solving the equation for q, we find the position of the image:

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{3.4}-\frac{1}{4.5}=0.0719 cm^{-1}\\q=\frac{1}{0.0719}=13.9 cm

Learn more about mirrors:

brainly.com/question/8737441

#LearnwithBrainly

3 0
3 years ago
What will happen to the period of a ball-on-a-spring if the ball is replaced by a smaller one with half the mass
Murrr4er [49]

When the ball on a spring is replaced by a smaller ball with half the mass :  The period decrease by 29%

<h3>Calculate the Period </h3>

We will apply the formula below to calculate period

T = 2\pi \sqrt{\frac{m}{k } }

 where :

T₁ / T₂ = \sqrt{\frac{m_{1} }{m_{2} } }    where m₂ = m₁ / 2

Therefore :

T₂ = \frac{T_{1} }{\sqrt{2} }   = 0.71 T

Hence we can conclude that the period will decrease by 29% ( i.e 100 - 71 ).

Learn more about Period calculation : brainly.com/question/10728818

4 0
2 years ago
does the pair of equilibria produced by a saddle-node bifurcation have to consist of one that is stable and one that is unstable
Amiraneli [1.4K]

This bifurcation is called a saddle-node bifurcation. In it, a pair of hyperbolic equilibria, one stable and one unstable, coalesce at the bifurcation point, annihilate each other and disappear.

<h3>What is a bifurcation equilibria?</h3>
  • The mathematical study of changes in a family of curves' qualitative or topological structure, such as the integral curves of a family of vector fields or the solutions to a family of differential equations, is known as bifurcation theory.
  • A bifurcation happens when a tiny, gradual change in a system's parameter values (the bifurcation parameters) results in an abrupt, "qualitative," or topological change in the system's behavior.
  • This term is most frequently used to refer to the mathematical study of dynamical systems.
  • Both continuous systems (represented by ordinary, delay, or partial differential equations) and discrete systems can experience bifurcations (described by maps).

To learn more about bifurcation equilibria, refer to

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3 0
2 years ago
Help please*_*
DochEvi [55]

Answer:

3.83×10⁻¹⁹ J

Explanation:

The energy of a photon can be found using the formula: E=hc/λ

  • h is Planck's Constant which is approximately 6.63×10⁻³⁴
  • c is the speed of light which we'll round to 3.00×10⁸
  • λ is the wavelength of the photon. You typed 5200 but that's not even within the visible light spectrum's wavelength range, so I'm going to assume you meant 520 nm; or 5.20×10⁻⁷ m.

Plugging all that info in should give approximately 3.83×10⁻¹⁹ Joules of energy.

(You could get slight variations depending on what you chose to round up or down or not at all.)

5 0
3 years ago
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