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dem82 [27]
3 years ago
15

Compared to the amount of radiation received from the Sun, about how much radiation does the surface of the earth receive from t

he atmosphere
Physics
1 answer:
babymother [125]3 years ago
5 0

Answer:

https://earthobservatory.nasa.gov/features/EnergyBalance#:~:text=The%20atmosphere%20absorbs%2023%20percent,surface%20radiates%20only%2012%20percent.

Explanation:

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Um objeto sobe verticalmente com velocidade de 10m/s . Quando sua altura é de 60m , uma parte desse objeto cai . Considerando g=
schepotkina [342]
Why is it in Spanish????????????????
6 0
3 years ago
A stationary siren creates an 894 Hz
valentina_108 [34]

Answer:

12.3 m/s

Explanation:

The Doppler equation describes how sound frequency depends on relative velocities:

fr = fs (c + vr)/(c + vs),

where fr is the frequency heard by the receiver,

fs is the frequency emitted at the source,

c is the speed of sound,

vr is the velocity of the receiver,

and vs is the velocity of the source.

Note: vr is positive if the receiver is moving towards the source, negative if away.

Conversely, vs is positive if the receiver is moving away from the source, and negative if towards.

Given:

fs = 894 Hz

fr = 926 Hz

c = 343 m/s

vs = 0 m/s

Find: vr

926 = 894 (343 + vr) / (343 + 0)

vr = 12.3

The speed of the car is 12.3 m/s.

5 0
3 years ago
A bond between a positively-charged particle and a negatively-charged particle is a(n) _______ bond.
weeeeeb [17]
The answer is an ionic bond.
6 0
3 years ago
As a mass on a spring moves farther from the equilibrium position, how do the velocity, acceleration, and force change
Umnica [9.8K]
Refer to the diagram shown below.

m =  the mass of the object
x = the distance of the object from the equilibrium position at time t.
v = the velocity of the object at time t
a = the acceleration of the object at time t
A =  the amplitude ( the maximum distance) of the mass from the equilibrium
        position

The oscillatory motion of the object (without damping) is given by
x(t) = A sin(ωt)
where
ω =  the circular frequency of the motion
T =  the period of the motion so that ω = (2π)/T

The velocity and acceleration are respectively
v(t) = ωA cos(ωt)
a(t) = -ω²A sin(ωt)

In the equilibrium position,
x is zero;
v is maximum;
a is zero.

At the farthest distance (A) from the equilibrium position,
x is maximum;
v is zero;
a is zero.

In the graphs shown, it is assumed (for illustrative purposes) that
A = 1 and T = 1.

6 0
3 years ago
Please need help on this one
jolli1 [7]

Answer:

The second answer from the top, no the energy in the wave pushed the water particles from above the earthquake in the opposite direction.

Explanation:

I believe this is the correct answer. Hope you do well

4 0
3 years ago
Read 2 more answers
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