Answer:
a) The strength of gravity decreases if one moved away from Jupiter
b) The strength of gravity increases if one fell into Jupiter
Explanation:
The gravitational attraction is given by Newton law of gravitation as follows;

Where;
G = The universal gravitational constant = 6.67408 × 10⁻¹¹ m³/(kg·s²)
M = The mass of Jupiter
m = The mass of the nearby body
R = The distance between the centers of Jupiter and the body
From the equation, we have that the gravitational strength varies inversely with the square of the separation distance between two bodies
Therefore, as one moves away, R increases, and the strength of gravity reduces
Similarly as the body falls into Jupiter, R, reduces the gravitational strength increases.
Answer:
The magnitude of the net force is √2F.
Explanation:
Since the two particles have the same charge Q, they exert the same force on the test charge; both attractive or repulsive. So, the angle between the two forces is 90° in any case. Now, as we know the magnitude of these forces and that they form a 90° angle, we can use the Pythagorean Theorem to calculate the magnitude of the resultant net force:

Then, it means that the net force acting on the test charge has a magnitude of √2F.
The astronaut would go the opposite direction due to Newton’s third law of -10N, -10N, -9N, -9N
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28.1 grams is 0.0281 kg.
43.278 kg - 0.0281 kg = 43.2499 or if you round -> 43.250
Answer:1.375metre per second square
Explanation: acceleration=(final velocity-initial velocity)÷time
acceleration=(8.6-4.2)÷3.2
Acceleration=4.4÷3.2
Acceleration=1.375 metre per second square