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Y_Kistochka [10]
4 years ago
8

which statement is a Hypothesis? A: Most of the earthworms moved to the shaded area during experiment. B: If an earthworm is giv

en a choice,its will move toward darkness rather than light. C: The earthworms must all be the species. D: Do earthworms prefer bright light or darkness.
Physics
1 answer:
True [87]4 years ago
3 0

Answer:

B

Explanation:

It's saying what you think

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A service elevator takes a load of garbage, mass 10.0 kg, from a floor of a skyscraper under construction, down to ground level,
kobusy [5.1K]

Answer:

The magnitude of the force the garbage exerts on the floor of the service elevator is 12 N

Explanation:

Given;

mass of the garbage, m = 10.0 kg

acceleration of the elevator, a = 1.2 m/s²

The magnitude of the force the garbage exerts on the floor of the service elevator is given by;

F = ma

F = 10 x 1.2

F = 12 N

Therefore, the magnitude of the force the garbage exerts on the floor of the service elevator is 12 N

8 0
4 years ago
An object is inside a room that has a constant temperature of 292 K. Via radiation, the object emits three times as much power a
maw [93]

Answer: Maybe he has the heater on

Explanation: If there is that much temperature then it has to be from something heated.

8 0
3 years ago
An effect analogous to two-slit interference can occur with sound waves, instead of light. In an open field, two speakers placed
Monica [59]

Answer:

2.72 m

Explanation:

wavelength of sound λ = velocity / frequency

= 340 / 1200

= .2833 m

Distance of point of  first constructive interference

= λ D / d ( D is distance of the screen and d is distance between source of sound.

Here D = 12.5 m

d = 1.3 m

λ D / d= ( .2833 x 12.5) / 1.3

= 2.72 m

Distance of point of  first constructive interference = 2.72 m

7 0
4 years ago
Consider a thin rod of mass 3.2 kg, length 1.2 m and uniform density. The rod is pivoted at one end on a frictionless horizontal
notsponge [240]

Answer:

the angular acceleration is 9.7 rad/s^{2}

Explanation:

given information:

mass of thin rod, m = 3.2 kg

the length of the rod, L = 1.2

angle, θ = 38

to find the acceleration of the rod, we can use the torque's formula as below,

τ = Iα

where

τ = torque

I = inertia

σ = acceleration

moment inertia of this rod, I

I = \frac{1}{3} mL^{2}

τ = F d, d = \frac{L}{2}cosθ

τ = m g \frac{L}{2}cosθ

now we can substitute the both equation,

τ = Iα

α = τ/I

  = (m g \frac{L}{2}cosθ)/(\frac{1}{3} mL^{2})

  = 3gcosθ/2L

  = 3 (9.8)cos 38°/(2 x 1.2)

  = 9.7 rad/s^{2}

 

3 0
3 years ago
Archerfish are tropical fish that hunt by shooting drops of water from their mouths at insects above the water’s surface to knoc
Mariulka [41]

Answer:

(d) 0.15 N

Explanation:

mass of the fish, m₁ = 65 g = 0.065 kg

initial velocity of the fish, u₁ = 0

mass of water expelled by the fish, m₂ = 0.30 g = 0.0003 kg

time during which the water was expelled, t = 5.0 ms = 5.0 x 10⁻³ s

velocity of the water, v = 2.5 m/s

The magnitude of force of the exerted water is equal to the magnitude of force the fish exerted on the water.

The magnitude of force of the exerted water is calculated as follows;

F = ma = m\frac{v}{t} \\\\F = \frac{mv}{t} \\\\F = \frac{m_2 \ \times \ v}{t} \\\\F = \frac{0.0003 \ \times \ 2.5}{5 \times 10^{-3}} \\\\F = 0.15 \ N

The correct option is D.

Therefore, the average force the fish exerts on the drop of water is 0.15 N.

8 0
3 years ago
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