Answer:
The magnitude of the force the garbage exerts on the floor of the service elevator is 12 N
Explanation:
Given;
mass of the garbage, m = 10.0 kg
acceleration of the elevator, a = 1.2 m/s²
The magnitude of the force the garbage exerts on the floor of the service elevator is given by;
F = ma
F = 10 x 1.2
F = 12 N
Therefore, the magnitude of the force the garbage exerts on the floor of the service elevator is 12 N
Answer: Maybe he has the heater on
Explanation: If there is that much temperature then it has to be from something heated.
Answer:
2.72 m
Explanation:
wavelength of sound λ = velocity / frequency
= 340 / 1200
= .2833 m
Distance of point of first constructive interference
= λ D / d ( D is distance of the screen and d is distance between source of sound.
Here D = 12.5 m
d = 1.3 m
λ D / d= ( .2833 x 12.5) / 1.3
= 2.72 m
Distance of point of first constructive interference = 2.72 m
Answer:
the angular acceleration is 9.7 rad/
Explanation:
given information:
mass of thin rod, m = 3.2 kg
the length of the rod, L = 1.2
angle, θ = 38
to find the acceleration of the rod, we can use the torque's formula as below,
τ = Iα
where
τ = torque
I = inertia
σ = acceleration
moment inertia of this rod, I
I =
τ = F d, d =
cosθ
τ = m g
cosθ
now we can substitute the both equation,
τ = Iα
α = τ/I
= (m g
cosθ)/(
)
= 3gcosθ/2L
= 3 (9.8)cos 38°/(2 x 1.2)
= 9.7 rad/
Answer:
(d) 0.15 N
Explanation:
mass of the fish, m₁ = 65 g = 0.065 kg
initial velocity of the fish, u₁ = 0
mass of water expelled by the fish, m₂ = 0.30 g = 0.0003 kg
time during which the water was expelled, t = 5.0 ms = 5.0 x 10⁻³ s
velocity of the water, v = 2.5 m/s
The magnitude of force of the exerted water is equal to the magnitude of force the fish exerted on the water.
The magnitude of force of the exerted water is calculated as follows;

The correct option is D.
Therefore, the average force the fish exerts on the drop of water is 0.15 N.