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Y_Kistochka [10]
3 years ago
8

which statement is a Hypothesis? A: Most of the earthworms moved to the shaded area during experiment. B: If an earthworm is giv

en a choice,its will move toward darkness rather than light. C: The earthworms must all be the species. D: Do earthworms prefer bright light or darkness.
Physics
1 answer:
True [87]3 years ago
3 0

Answer:

B

Explanation:

It's saying what you think

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What part of an atom is responsible for producing magnetic fields
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Electrons is the part of the atom that creats a magnetic feild

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The temperature of a sample of silver increased by 24.0 °C when 269 J of heat was applied. What is the mass of the sample?
statuscvo [17]

Answer:

Mass of the silver will be equal to 46.70 gram

Explanation:

We have given heat required to raise the temperature of silver by 24°C is 269 J , so \Delta T=24^{\circ}C

Specific heat of silver = 0.240 J/gram°C

We have to find the mass of silver

We know that heat required is given by

Q=mc\Delta T, here m is mass, c is specific heat of silver and \Delta T is rise in temperature

So 269=m\times 0.240\times 24

m = 46.70 gram

So mass of the silver will be equal to 46.70 gram

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3 years ago
4. A disobedient student dropped his Physics textbook (mass 0.1kg) from the window (15m above the ground). How fast was it going
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Answer:

v= 17.15 m/s

Explanation:

mass of the book=0.1 Kg

height above ground, h= 15 m

Using conservation of energy

Potential energy is converted into kinetic energy

mgh = \frac{1}{2}mv^2

v=\sqrt{2gh}

v=\sqrt{2\times 9.8\times 15}

v=\sqrt{294}

v= 17.15 m/s

Hence, the book will hit the ground at the speed of 17.15 m/s.

8 0
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James makes a treasure map to locate a secret item on McEachern Campus. He uses the
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Answer:

south

Explanation:

3 0
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Read 2 more answers
A 1560-kilogram truck moving with a speed of 28.0 m/s runs into the rear end of a 1070-kilogram stationary car. If the collision
Nimfa-mama [501]

Answer:

Δ KE =  249158.6 kJ  

Explanation:

given data

Truck mass  M =  1560 Kg

Truck initial speed, u = 28 m/s

mass of car m = 1070 Kg

initial speed of car u1 = 0 m/s

solution

first we get here final speed by using conservation of momentum  that is express as

Mu = (M+m) V     .......................1

put here  value we get

1560 × 28 = (1560 + 1070 ) V

solve it we get

final speed V = 16.60 m/s

and

Change in kinetic energy  will be here

Δ KE =   \frac{1}{2} Mu^2 - \frac{1}{2}(M+m)V^2         .................2

put here value and we get

 Δ KE = \frac{1}{2}\times 1560\times 28^2 - \frac{1}{2}\times (1560 + 1070)\times 16.60^2  

solve it we get

Δ KE =  249158.6 kJ  

6 0
3 years ago
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