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Inessa05 [86]
2 years ago
12

A rocket initially at rest accelerates at a rate of 99. 0 meters/second2. Calculate the distance covered by the rocket if it att

ains a final velocity of 445 meters/second after 4. 50 seconds. A. 2. 50 × 102 meters B. 1. 00 × 103 meters C. 5. 05 × 102 meters D. 2. 00 × 103 meters E. 1. 00 × 102 meters.
Physics
1 answer:
creativ13 [48]2 years ago
7 0

The rocket will cover 1 \times  10^3\rm \ m distance in 4. 5 s. Acceleration can be defined as the change in velocity.

<h3>What is acceleration?</h3>

Acceleration can be defined as the change in speed or the direction of the object.

From kinamatic equation:

D = v_{t} +\dfrac 12at^2

Where,

D - final velocity =  445 m/s

v_0 -  initial valocity = 0 m/s

a - acceleration = 99. 0 m/s²

t - time =  4. 50 s

Put the values in the formula,

D = 0\times  ( 4.5) + \dfrac12\times (99)(4.5)^2\\\\D = 1002 {\rm \ m}\\\\D = 1 \times  10^3\rm \ m

Therefore, the rocket will cover 1 \times  10^3\rm \ m distance in 4. 5 s.

Learn more about Acceleration :

brainly.com/question/2697545

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So, these types of waves are called longitudinal waves.


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Compare the momentum of a 6,300-kg elephant walking 0.11 m/s and a 50-kg dolphin swimming 10.4 m/s. your answer
bogdanovich [222]
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Peter’s body supplies a force of 500 N to run up a 10-m hill in 10 s. How much power is involved in Peter’s run up the hill? Exp
shutvik [7]

Answer: 500 Watts

Explanation:

Power P is the speed with which work W is done. Its unit is Watts (W), being 1 W=\frac{1 Joule}{1 s}.

Power is mathematically expressed as:

P=\frac{W}{t} (1)

Where t is the time during which work W  is performed.

On the other hand, the Work W done by a Force F refers to the release of potential energy from a body that is moved by the application of that force to overcome a resistance along a path.  It is a scalar magnitude, and its unit in the International System of Units is the Joule (like energy). Therefore, 1 Joule is the work done by a force of 1 Newton when moving an object, in the direction of the force, along 1 meter (1J=(1N)(1m)=Nm  ).

When the applied force is constant and the direction of the force and the direction of the movement are parallel, the equation to calculate it is:  

W=(F)(d) (2)

In this case, we have the following data:

F=500 N

d=10 m

t=10 s

So, let's calculate the work done by Peter and then find how much power is involved:

From (2):

W=(500 N)(10 m) (3)

W=5000 J (4)

Substituting (4) in (1):

P=\frac{5000 J}{10 s} (5)

Finally:

P=500 W

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2 years ago
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