The statement that the friend made is not true. most of the mass of the plant is from carbon. the carbon comes from carbon dioxide which is used during photosynthesis. the left over carbon from photosynthesis is used to to help the plant gain mass. there is a process for this which is called cellular respiration
Using the Henderson-Hasselbalch equation on the solution before HCl addition: pH = pKa + log([A-]/[HA]) 8.0 = 7.4 + log([A-]/[HA]); [A-]/[HA] = 4.0. (equation 1) Also, 0.1 L * 1.0 mol/L = 0.1 moles total of the compound. Therefore, [A-] + [HA] = 0.1 (equation 2) Solving the simultaneous equations 1 and 2 gives: A- = 0.08 moles AH = 0.02 moles Adding strong acid reduces A- and increases AH by the same amount. 0.03 L * 1 mol/L = 0.03 moles HCl will be added, soA- = 0.08 - 0.03 = 0.05 moles AH = 0.02 + 0.03 = 0.05 moles Therefore, after HCl addition, [A-]/[HA] = 0.05 / 0.05 = 1.0 Resubstituting into the Henderson-Hasselbalch equation: pH = 7.4 + log(1.0) = 7.4, the final pH.
Answer:
b. 6.02 x 1023 molecules
Explanation:
The formula mass of ammonia is 14 + 1 × 3 = 17.
The number of moles in 27.6g ammonia is 27.6 ÷ 17 = 1.62 mol.
A mole is 6.02 × 10²³, so the number of hydrogen atoms in a 1.62 moles of ammonia is 1.62 × 6.02 × 10²³ × 3 = 2.93 × 10² atoms.
Answer:
The ratio of staggered to eclipsed conformers is 134
Explanation:
It is possible to determine the ratio of staggered to eclipsed conformers of a reactant, using the equilibrium:
Staggered ⇄ Eclipsed
Keq = [Eclipsed] / [Staggered]
That means Keq is equal to the ratio we need to find:
Using:
G˚= -RTln Keq
<em>Where G° = -12133.6J/mol</em>
<em>R is gas constant: 8.314J/molK</em>
<em>T is absolute temperature: 298K</em>
<em />
-12133.6J/mol= -8.314J/molK*298K ln Keq
4.8974 = ln Keq
134 = Keq = [Eclipsed] / [Staggered]
<h3>The ratio of staggered to eclipsed conformers is 134</h3>
