Calculate the whole-number ratio of staggered to eclipsed conformers that are present at room temperature. Use the Actual G˚ bar
1 answer:
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Answer:
The value of Kp at this temperature is 7.44*10⁻³
Explanation:
Chemical equilibrium is established when there are two opposite reactions that take place simultaneously at the same speed.
For the general chemical equation for a homogeneous gas phase system:
aA + bB ⇔ cC + dD
where a, b, c and d are the stoichiometric coefficients of compounds A, B, C and D, the equilibrium constant Kp is determined by the following expression:
Where Px is the partial pressure of each of the components once equilibrium has been reached and they are expressed in atmospheres. The equilibrium constant Kp depends solely on temperature and is dimensionless.
In the case of the reaction:
2 HI (g) ⇔ H₂ (g) + I₂ (g)
the equilibrium constant Kp is determined by the following expression:
The system comes to equilibrium at 425 °C, and
- PHI = 0.794 atm
- PH2 = 0.0685 atm
- PI2 = 0.0685 atm
Replacing:
Kp=7.44*10⁻³
<u><em>The value of Kp at this temperature is 7.44*10⁻³</em></u>
<u>Answer:</u> 0.0237 g of calcium carbonate would be required to neutralize the given amount of HCl
<u>Explanation:</u>
pH is defined as the negative logarithm of hydrogen ion concentration present in the solution
.....(1)
Given value of pH = 1.5
Putting values in equation 1:
Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:
.....(2)
We are given:
Volume of solution = 15.0 mL
Molarity of HCl = 0.0316 M
Putting values in equation 2:
The chemical equation for the reaction of HCl and calcium carbonate follows:
By the stoichiometry of the reaction:
2 moles of HCl reacts with 1 mole of calcium carbonate
So, of HCl will react with =
of calcium carbonate
The number of moles is defined as the ratio of the mass of a substance to its molar mass.
Moles of calcium carbonate =
Molar mass of calcium carbonate = 100.01 g/mol
Putting values in the above equation:
Hence, 0.0237 g of calcium carbonate would be required to neutralize the given amount of HCl