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erik [133]
3 years ago
9

A distance-time graph indicates that an object travels 2 m in 2 s and then travels another 80 m during the next 40 s. What is th

e average speed of the object?
Physics
1 answer:
GaryK [48]3 years ago
6 0
To find the average speed, we must calculate the total distance covered by the object and then divide it by the total time of the motion.

The total distance covered by the object is
S=2m+80m=82 m
while the total time of the motion is
t=2s+40 s=42 s

Therefore, the average speed of the object is
v= \frac{S}{t}= \frac{82 m}{42 s}=1.95 m/s
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An electron in the n = 5 level of an h atom emits a photon of wavelength 1282.17 nm. to what energy level does the electron move
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This is an interesting (read tricky!) variation of Rydberg Eqn calculation.
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8 0
3 years ago
Read 2 more answers
A vector has an x-component
9966 [12]

Explanation:

The magnitude of a vector v can be found using Pythagorean's theorem.

||v|| = √(vₓ² + vᵧ²)

||v|| = √((-309)² + (187)²)

||v|| ≈ 361

You can find the angle of a vector using trigonometry.

tan θ = vᵧ / vₓ

tan θ = 187 / -309

θ ≈ 149° or θ ≈ 329°

vₓ is negative and vᵧ is positive, so θ must be in the second quadrant.  Therefore, θ ≈ 149°.

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