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erik [133]
3 years ago
9

A distance-time graph indicates that an object travels 2 m in 2 s and then travels another 80 m during the next 40 s. What is th

e average speed of the object?
Physics
1 answer:
GaryK [48]3 years ago
6 0
To find the average speed, we must calculate the total distance covered by the object and then divide it by the total time of the motion.

The total distance covered by the object is
S=2m+80m=82 m
while the total time of the motion is
t=2s+40 s=42 s

Therefore, the average speed of the object is
v= \frac{S}{t}= \frac{82 m}{42 s}=1.95 m/s
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Answer:

The initial energy emission occurs by 80% or more in the form of gamma rays but these are quickly absorbed and dispersed mostly by air in little more than a microsecond, converting gamma radiation into thermal radiation (thermal pulse ) and kinetic energy (shock wave) which are actually the two dominant effects in the initial moments of the explosion. The rest of the energy is released in the form of delayed radiation (fallout or fallout) and is not always counted when measuring the performance of the explosion.

Explanation:

High altitude explosions produce greater damage and extreme radiation flux due to lower air density (photons encounter less opposition) and consequently a higher blast wave is generated.

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A​ blimp, suspended in the air at a height of 600 ​feet, lies directly over a line from a sports stadium to a planetarium. If th
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Answer:

1946 ft

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One clue we can observe that means a chemical reaction has occurred is the formation of light. What is one chemical reaction you
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2 years ago
F all of the energy in a falling object's gravitational potential energy store is transferred to its kinetic energy store by the
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The options are not shown, so let's derive the relationship.

For an object that is at a height H above the ground, and is not moving, the potential energy will be:

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Now, the kinetic energy of an object can be written as:

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So we expressed the final velocity (the velocity at which the object impacts the ground) in terms of the height, H.

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2 years ago
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