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Kisachek [45]
3 years ago
10

In an extrasolar planetary system containing a single planet, the parent star is measured to move about its center of mass every

24 years. Given this, what is the orbital period of the planet?
Physics
1 answer:
Mademuasel [1]3 years ago
4 0

Answer:

Orbital Time Period is 24 years

Explanation:

This can be explained by the definition of time period.

Time period can be defined as the time taken by an object to complete one cycle, here, time taken to complete one revolution.

Also, we know that an extra solar planet which is also called as an exo planet is that planet which is outside our solar system and orbits any star other than our sun. The system in consideration is extra solar system with a single planet.

Therefore, the time taken by the parent star to move about its mass center is the orbital time period that is 24 years.

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A unit of time sometimes used in microscopic physics is the "shake". One shake equals 10−8 s.
Lady_Fox [76]

Answer:

(a) There are 3.17 times more shakes in a second than seconds in a year.

(b) Humans have existed for 9067.72 universe seconds.

Explanation:

(a) First we calcule how many seconds are in a year. One year have 365 days, one day has 24 hours, one hour has 60 minutes and one minute has 60 seconds, so:

60s*60*24*365=3.1536*10^7s

Now, we calculate how many shakes are in a second:

1s*\frac{1shake}{10^{-8}s}=10^8shakes

Finally, we calculate how many more shakes in a second are there than seconds in a year:

\frac{10^8s}{3.1536*10^7s}=3.17

(b) Using a simple rule of three we can calculate  how many "universe seconds" have humans existed, recall that 1 day has 86400 seconds:

1010 years--------->86400s

106 years----------> x seconds

x=\frac{106y*86400s}{1010y}=9067.72s

3 0
3 years ago
A painter sits on a scaffold that is connected to a rope passing over a pulley. The other end of the rope rests in the hands of
Doss [256]

Solution :

a). From Newtons second law,

F = ma

The total tension force is 2T.

∴ 2T - (m + M)g = (m+ M)a

Then

$a=\frac{2T-(m+M)g}{m+M}$

$a=\frac{2\times 600-(52+63)9.8}{52+63}$

   $=0.63 \ m/s^2$

b). From the person,

   F = ma

 T - Mg + N = Ma

or N = Ma + Mg - T

        = (63 x 9.8) + (52 x 9.8) - 600

        = 617.4 + 509.6 - 600

        = 527 N

6 0
3 years ago
A car headed north at 15.0 m/s experiences an acceleration of 2.50 m/s2 for 3.00 s. What is the final velocity of the car?
nikitadnepr [17]

Answer:

i dond no can you put another question

4 0
2 years ago
1. How do energy and matter recycle in a closed-loop system?
Makovka662 [10]

Answer:

In a closed-loop system, matter is used to generate energy, and the energy generated is used to produce matter, and the cycle goes on without end.

Explanation:

A closed-loop system is one in which materials or energy is recycled without end through a production cycle. This means that a raw material is used to produce a finished product, and the finished product at the end of its use cycle is converted back and used as a raw material to produce more of it again. Energy and matter can also be cycled in the same way in an energy and matter closed-loop system, converting matter to energy, and the energy is put back into the production of more of the matter.

7 0
3 years ago
The reason carbon dating works is that A. there is so much non-radioactive carbon dioxide in the air. B. when a plant or animal
yuradex [85]
D.  There is a known constant concentration of C14 in Nature.  As we consume living things to survive our bodies (made of carbon) stop replenishing our body's carbon (we stop eating) and start to decay.  Since we know the 1/2 life of C14 and the ratio of C14 to normal C12 we can determine fairly accurately how long ago a thing stopped consuming carbon (e.g. when it died)
7 0
3 years ago
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