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4 years ago

What is the chemical formula for the compound formed from potassium and sulfur

Chemistry

1 answer:

irakobra [83]4 years ago

4 0

Equation: 2K + S --> K2S Chemical formula: K2S

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What is the molar concentration of Pb+ in a solution that contains 6.73 ppm of

Katarina [22]

Answer:

2.03 × 10⁻⁵ M

Explanation:

Step 1: Given data

Concentration of Pb(NO₃)₂: 6.73 ppm = 6.73 mg/L

Step 2: Convert 6.73 mg/L to mol/L

The molar mass of 331.2 g/mol.

6.73 × 10⁻³ g/L × 1 mol/331.2 g = 2.03 × 10⁻⁵ mol/L = 2.03 × 10⁻⁵ M

Step 3: Calculate the molar concentration of Pb²⁺

Let's consider the ionization of Pb(NO₃)₂.

Pb(NO₃)₂(aq) ⇒ Pb²⁺(aq) + 2 NO₃⁻(aq)

The molar ratio of Pb(NO₃)₂ to Pb²⁺ is 1:1. The molar concentration of Pb²⁺ is 1/1 × 2.03 × 10⁻⁵ M = 2.03 × 10⁻⁵ M.

8 0

3 years ago

The velocity is ___ when the distance is kept the same and the time is halved

klemol [59]

Answer:

Velocity = distance / time

if distance is same and time is 1/2

Velocity = distance / time/2

velocity = 2 (distance /time)

Velocity,= 2 * velocity

Velocity will be doubled

6 0

2 years ago

A NaOH solution is standardized using the monoprotic primary standard potassium hydrogen phthalate, KHP (204.22 g/mol.) If 0.698

kakasveta [241]

Answer:

0.07789 M is the sodium hydroxide concentration.

Explanation:

Mass of potassium hydrogen phthalate = 0.6986 g

Molar mass of potassium hydrogen phthalate = 204.22 g/mol

Moles of potassium hydrogen phthalate = $\frac{0.6986 g}{204.22 g/mol}=0.003421 mol$

$NaOH+KHP\rightarrow NaKP+H_2O$

According to reaction , 1 mole og KHp reactswith 1 mole of NaOH , then 0.003421 moles of KHp will react with :

$\frac{1}{1}\times 0.003421 mol=0.003421 mol$

Moles of NaOH = 0.003421 mole

Volume of NaOH solution = 43.92 ml = 0.04392 L ( 1 mL = 0.001L)

$Concentration=\frac{Moles}{Volume(L)}$

Concentration of NaOH :

$\frac{0.003421 mol}{0.04392 L}=0.07789 M$

0.07789 M is the sodium hydroxide concentration.

5 0

3 years ago

How much water would I need to add to 500 ml of a 2.4 M KCL solution to make a 1.0 M solution

Yuki888 [10]

the answer is 700ml

5 0

3 years ago

What is the maximum mass of s8 that can be produced by combining 89.0 g of each reactant?

lidiya [134]

Answer : We can produce 125.7 g of $S_{8}$ .

Explanation : The reaction will be

$8SO_{2} + 16H_{2}S -----> 3S_{8} + 16H_{2}O$

The molecular mass of $SO_{2}$ is 64.1 g/mol

and molecular mass of $H_{2}S$ is 34.1 g/mol

For every mole of $SO_{2}$ we would need twice of $H_{2}S$ moles, so for every 3 moles of $S_{8}$ we need 16 moles of $H_{2}S$

Now, we can calculate number of moles $S_{8}$

2.61 X (3/16) = 0.49 moles

Here, the molecular mass of $S_{8}$ is 256.8 g

multiplying it with the number of 0.49 moles we get, 256.8 X 0.49 = 125.7 g of $S_{8}$ .

Hence, 125.7 g of $S_{8}$ will be produced.

8 0

3 years ago