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atroni [7]
4 years ago
11

How are elements and compounds related

Chemistry
1 answer:
Lisa [10]4 years ago
5 0
Elements are a one of a class of substances that cannot be seperwted into simpler substances by chemicalk means. Compounds is a substance formed when two or more chemical elements are chemically bonded together. Relation: When two elements or more are formed chemically together its called a compound without elements there won't be compounds and without compounds there won't be elements.
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What is the mass of 12.83 mL of acetic acid (98% wt/wt)?
Kaylis [27]

Answer:

The mass of the acetic acid is 13.5 g

Explanation:

Given;

weight percent of the acetic acid (ratio of solute to total solution), w/w = 98 %

volume of acetic acid, v = 12.83 mL

density of acetic acid, ρ = 1.05 g/mL

density is given by;

density = mass / volume

mass = density x volume

mass of the acetic acid in 12.83 mL =  1.05 g/mL x 12.83 mL

mass of the acetic acid in 12.83 mL = 13.5 g

Therefore, the mass of the acetic acid is 13.5 g

3 0
3 years ago
If an aquatic animal relies on photosynthesis to survive, in which ocean zone would it be most successful?
Leya [2.2K]
It is the epipelagic zone.
3 0
4 years ago
Read 2 more answers
Polar bears are well adapted to the Arctic environment due to their white
s2008m [1.1K]

answer: white fur works as a camouflage against the white snow, allowing polar bears an advantage when hunting for food and hiding from predators

6 0
3 years ago
What's the structure of Cl2O? Is it polar or non-polar?
lisabon 2012 [21]
Answer: C) Bent or angular, polar
Explanation:
The central atom oxygen has two lone pairs and two bond pairs in . The number of electron pairs are 4, that means the hybridization will be and the electronic geometry of the molecule will be tetrahedral. But as there are two lone pair of atoms around the central oxygen atom, repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be bent shape.
The compound is polar as the net dipole moment of oxygen - fluoride bonds do not cancel each other out.

3 0
3 years ago
Use the standard half-cell potentials listed below to calculate the standard cell potential for the following reaction occurring
ludmilkaskok [199]

Answer:

1.20 V

Explanation:

Pb(s) + Br_2(l)\rightarrow Pb^{2+}(aq) + 2Br^-(aq)

Here Pb undergoes oxidation by loss of electrons, thus act as anode. Bromine undergoes reduction by gain of electrons and thus act as cathode.

E^0=E^0_{cathode}- E^0_{anode}

Where both E^0 are standard reduction potentials.

Given,

Pb^{2+}(aq) + 2 e^-\rightarrow Pb(s)

E^0_{[Pb^{2+}/Pb]}= -0.13\ V

Br_2(l) + 2 e^-\rightarrow 2 Br(aq)

E^0_{[Br_2/Br^{-}]}=+1.07\ V

E^0=E^0_{[Br_2/Br^{-}]}- E^0_{[Pb^{2+}/Pb]}

E^0=+1.07- (-0.13)\ V=1.20\ V

6 0
4 years ago
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