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3 years ago

_ + _ = H2O + LiBrO3 Complete and balance the equation representing neutralization reaction.

1 answer:

5 0

When an acid reacts with a base its called a neutralisation reaction and products of the reaction are salt and water.
this is called neutralisation as hydrogen ions in acid react with hydroxide ions in base and form water.
the cation in base reacts with anion in acid and forms a salt.
In the reaction given the salt formed is LiBrO₃
in the salt formed the cation is Li⁺ and anion is BrO₃⁻
therefore base is LiOH and acid is HBrO₃
neutralisation reaction is therefore
LiOH + HBrO₃ ---> LiBrO₃ + H₂O

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$\lambda$ = Wavelength of radiation

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$n_i$ = Initial energy level = 3

Putting the values in above equation, we get:

$\frac{1}{\lambda }=1.097\times 10^7m^{-1}\left(\frac{1}{2^2}-\frac{1}{3^2} \right )\\\\\lambda =\frac{1}{1.524\times 10^6m^{-1}}=6.56\times 10^{-7}m$

Converting this into nanometers, we use the conversion factor:

$1m=10^9nm$

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3 years ago

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Explanation:

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1 year ago

___ + ___ = H2O + LiBrO3 Complete and balance the equation representing neutralization reaction.

_ + _ = H2O + LiBrO3 Complete and balance the equation representing neutralization reaction.