3 years ago

Which statement about a Ferris wheel is true?

Physics

1 answer:

nikitadnepr [17]3 years ago

6 0

Answer:the imput force is applied to the axle

Explanation:

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Is brainly working for you guys?

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Answer:

Yeah whats it doing for you?

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3 years ago

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A car accelerates at a rate of 3 m/s^2. If its original speed is 8 m/s, how many seconds will it take the car to reach a final s

kkurt [141]

Answer:

$\Large \boxed{\mathrm{5.67 \ seconds }}$

Explanation:

$\displaystyle \mathrm{acceleration \ = \ \frac{final \ velocity - initial \ velocity }{elapsed \ time}}$

$\displaystyle A \ = \ \frac{V_f - V_i }{t}$

$\displaystyle 3 \ = \ \frac{25 - 8 }{t}$

$\displaystyle 3 \ = \ \frac{17 }{t}$

$\displaystyle t \ = \ \frac{17 }{3} \approx 5.67$

4 0

3 years ago

Ben and Jerry went for a drive. They decided to stop for a snack and have some ice cream. How fast did they drive on their way t

raketka [301]

Answer: B) 30 km/h

Explanation:

The speed of Ben and Jerry on their way to the store is given by

$v=\frac{d}{t}$

where

d is the distance they covered

t is the time they took

From the graph, we see that Ben and Jerry travelled for a distance of d=60 km in a time of t=2 h, so their speed is

$v=\frac{60 km}{2 h}=30 km/h$

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3 years ago

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Suppose you want to search for brown dwarfs using a space telescope. Will you design your telescope to detect light in the ultra

Lisa [10]

Answer:

infrared part of the spectrum

Explanation:

brown dwarfs are relatively cool and have temperatures of about 2000 K emitting their light in the infrared and practically none in the ultraviolet part of the spectrum.

3 0

4 years ago

At what angle should the roadway on a curve with a 50m radius be banked to allow cars to negotiate the curve at 12 m/s even if t

kari74 [83]

Answer:

The road bank angle is 16.38⁰.

Explanation:

radius of curvature of the road, r = 50 m

allowable speed of car on the road, v = 12 m/s

The bank angle is calculated as;

$\theta = tan^{-1} (\frac{v^2}{gr} )$

where;

θ is the road bank angle

g is acceleration due to gravity = 9.8 m/s²

$\theta = tan^{-1} (\frac{v^2}{gr} )\\\\\theta = tan^{-1} (\frac{12^2}{9.8 \times 50} )\\\\\theta = tan^{-1} ( 0.2939)\\\\\theta = 16.38 ^0$

Therefore, the road bank angle is 16.38⁰.

8 0

3 years ago