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Dmitry [639]
2 years ago
8

In the absence of a gravitational force, the weight of a body is?

Physics
1 answer:
azamat2 years ago
5 0

Answer:

0

Explanation:

Weight = mass x gravity

if gravity = 0 then Weight =0 as well

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Allushta [10]

Answer:

260° C

Explanation:

si

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Which of these samples of water has the most internal energy?
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1kg steam will have the maximum energy

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3 years ago
Two cars, a Porsche Boxster convertible and a Toyota Scion xB, are traveling at constant speeds in the same direction. Suppose,
fenix001 [56]

Answer:

It will take 29.31 seconds for the Boxster to catch the Scion

Explanation:

Given the data in the question;

lets say Toyota Scion xB is car A and Porsche Boxster convertible is B and Toyota Scion xB is car A

the distance travelled by car A is

x = V_{A} × t

where  V_{A} is the speed of the car and t is time

the distance travelled by car B before reaching car A will be;

x + x₀ = V_{B} × t

Now lets replace x by V_{A} × t

so

(V_{A} × t) + x₀ = V_{B} × t

x₀ = (V_{B} × t) - (V_{A} × t)

x₀ = t (V_{B} - V_{A})

t = x₀ /  (V_{B} - V_{A})

so we substitute

t = 170 m  /  (24.4 - 18.6)  

t = 170 / 5.8

t = 29.31 s

Therefore; it will take 29.31 s for the Boxster to catch the Scion

8 0
3 years ago
If the model below represents a volcano and its relationship to the layers of the Earth, from which of the Earth's layers does t
just olya [345]
Magma comes from the core
8 0
3 years ago
A car is being tested for safety by colliding it with a brick wall.The 1300 kg car is initially driving towards the wall at a sp
serg [7]

Answer:

44200 N

Explanation:

To calculate the average force exerted on the car, we will use the following equation

\begin{gathered} Ft=\Delta p \\ Ft=m(v_f-v_i) \end{gathered}

Where F is the average force, t is the time, m is the mass, vf is the final velocity and vi is the initial velocity of the car.

Replacing t = 0.5s, m = 1300 kg, vf = -2 m/s, and vi = 15 m/s and solving for F, we get

\begin{gathered} F(0.5s)=(1300\text{ kg\rparen\lparen-2 m/s - 15 m/s\rparen} \\ F(0.5s)=(1300\text{ kg\rparen\lparen-17 m/s\rparen} \\ F(0.5s)=-22100\text{ kg m/s} \\ F=\frac{-22100\text{ kg m/s}}{0.5\text{ s}} \\ F=-44200\text{ N} \end{gathered}

Therefore, the average force exerted on the car by the wall was 44200 N

4 0
1 year ago
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