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3 years ago

What is the velocity of a car that traveled a total of 75 kilometers north in 1.5 hours?

1 answer:

swat323 years ago

7 0

The car's velocity is (distance + direction) / (time) =

(75 km-north) / (1.5 hrs) =

(75/1.5) (km-north/hr) = 50 km/hr north.

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The slope of the the line is the _______ of the object

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3 years ago

Substitute the value 26.7 (or the exact value of 80/3) for x in the first of the original equation (x + y = 40) to find the valu

Tatiana [17]

Complete Question

The complete question is shown on the first uploaded image

Answer:

the value of $y = 13.3$

Explanation:

From the question we are told that

The equation is (x + y = 40)

The first value of x is $x_1 = 26.7$

The second equation is (0.75x + 1.5y = 40)

So substituting $x_1$

$26.7 + y = 40$

=> $y = 13.3$

Now substituting y and $x_1$ into second equation

$0.75(26.7) + (1.5* 13.3) = 40$

=> $40 = 40$

So $y = 13.3$

4 0

3 years ago

When sitting in the tree the cat has a total of 1375J in its Gravitational potential store. What is the maximum amount of energy

Murrr4er [49]

Answer:

1375J

Explanation:

The gravitational potential/potential energy of the at the top of the tree which is the energy by virtue of its position.

P.E = mgh

mass = m

Acceleration due to gravity = g

height = h

At the top of the tree, the value of h (height) is high resulting in the gravitational potential. When the cat lands on the ground, the value of h is zero, the the gravitational potential would be zero and all the potential energy have been converted to other forms of energy.

Therefore, the total gravitational potential store is equal to the maximum amount of energy that can be transferred which is equal to 1375J.

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3 years ago

Se dispone de dos vasos con agua a 20 grados y queremos calentarlo hasta alcanzar 50 grados. Si el primero contiene 0,5l y el se

BigorU [14]

Answer:

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Explanation:

To know what amount of water you take into account the specific heat of the water. The specific heat of water is:

$c_{water}=4186\frac{J}{kg\°C}$

Thus, 4186 J of energy are needed to icrease the temperature of 1 kg water in 1°C. Then, more grams of water will need more energy.

You have that one cup has 0.5 L and the other one has 750mL = 0.75L

The second cup of water will need more heat because the amount of water contained in the second cup is greater than in the first cup with 0.5L

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3 years ago