• t2<span>). Furthermore, since there is no horizontal acceleration, the horizontal distance traveled by the projectile each second is a constant value - the projectile travels a horizontal distance of </span>20 meters<span> each second. This is consistent with the initial horizontal velocity of </span>20 m<span>/s.
</span>
Well because it has momentum and it needs to be slowed down.
Answer:
the coefficient of Kinetic friction between the tires and road is 0.38
Option A) .38 is the correct answer
Explanation:
Given that;
final velocity v = 0
initial velocity u = 15m/s
time taken t = 4 s
acceleration a = ?
from the equation of motion
v = u + at
we substitute
0 = 15 + a × 4
acceleration a = -15/4 = - 3.75 m/s²
the negative sign tells us that its a deacceleration so the sign can be ignored.
Deacceleration due to friction a = μ × g
we substitute
3.75 = μ × 9.8
μ = 3.75 / 9.8 = 0.3826 ≈ 0.38
Therefore the coefficient of Kinetic friction between the tires and road is 0.38
Option A) .38 is the correct answer
Answer:
To have a positive job, the two vectors must have the same direction
Explanation:
Work is a scalar defined as the scalar product of two vectors, the froce and the displacement. To have a positive job, the two vectors must have
collinear and that their arrows point in the same direction.
You can also appreciate this from the work equation
W = F. r
bold indicate vector
W = F r cos θ
With θ the angle between force and displacement
