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IrinaK [193]
2 years ago
8

An auditorium measures 43.0m × 18.0m × 15.0m. The density of air is 1.20 kg/m3. What is the volume of the room in cubic feet? (D

o not input units. Note that 1m = 3.28ft)
My Answer 43x18x15 = 11,610 m^3 11,610m3 * 3.28ft m = 38,080.8 ft When I used this number I got it incorrect and it said for me to use less figures
Physics
1 answer:
frez [133]2 years ago
5 0
The question here would be what is the volume of the room. The density of air that is given has no use. We simply multiply the dimensions given of the room to determine  the volume.

<span>43.0m × 18.0m × 15.0m = 11610m^3 ( 3.28 ft / 1 m)^3 = 4.09 x 10^5 ft^3</span>
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What is the stretch when you pull with a force of 25 N on a spring with a spring constant of 8 N/m? *
Pani-rosa [81]

Hooke's Law

\tt F=k.\Delta x

k = spring constant

x = stretch

F = force

Input the value

\tt \Delta x=\dfrac{F}{k}=\dfrac{25}{8}=3.125\rightarrow 3.13\:m

7 0
2 years ago
Water flows from a large drainage pipe at a rate of 950 gal/min. What is this volume rate of flow in (a) m3/s , (b) liters/min,
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Answer:

0.05997\ m^3/s

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Explanation:

1\ gal/min=\dfrac{1}{264\times 60}\\\Rightarrow 950\ gal/min=950\times \dfrac{1}{264\times 60}\\\Rightarrow 950\ gal/min=0.05997\ m^3/s

Volume rate of flow is 0.05997\ m^3/s

1\ gal/min=3.78541\ L/min\\\Rightarrow 950\ gal/min=950\times 3.78541=3596.1395\ L/min

Volume rate of flow is 3596.1395\ L/min

1\ gal/min=\dfrac{1}{7.481\times 60}\\\Rightarrow 950\ gal/min=950\times \dfrac{1}{7.481\times 60}\\\Rightarrow 950\ gal/min=2.11647\ ft^3/s

Volume rate of flow is 2.11647\ ft^3/s

6 0
3 years ago
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Answer:

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Explanation:

6 0
2 years ago
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Can someone pls help me and give me the answers i will mark brainliest :3
Katyanochek1 [597]

Answer:

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8 0
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Answer:

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Explanation:

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