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3 years ago

6

You are driving your car at a speed of 60 miles per hour, when you cross into Canada. Canada measures their speed in kilometers

per hour, and you need to figure out how fast you are going!

1 answer:

Flauer [41]3 years ago

8 0

Answer:

Answer:

I don't know

Explanation:

I don't know

Explanation:

Answer:

I don't know

Explanation:

I don't know

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Calculate the frequency of the wave shown below.

jenyasd209 [6]

$\color{skyblue}{ \underline{ \frak { \: option \: ( \: c \: ) = 2 \: hertz ✓}}}$

$\: \:$

Given :

Wavelength ( λ ) = 2 m

$\: \:$

Speed = 4 m/s

$\: \:$

We, have to find frequency :

$\:$

$\large \tt \: Frequency = \frac{Speed}{Wavelength ( \: λ \: )}$

$\: \:$

$\large \tt \: Frequency = \frac{4}{2}$

$\: \:$

$\large \tt \: Frequency = \cancel \frac{4}{2}$

$\: \:$

$\pink{ \boxed{\large \tt \: Frequency =2 \: Hertz ✓}}$

$\: \:$

Hope Helps!

5 0

1 year ago

Work output of a large machine in a factory is 89,000 joules, and it’s input is 102,000 joules. Work output of a similar machine

mojhsa [17]

(89000/102000)×100
=87.25%

(92000/104000)×100
=88.46%

efficiency is (output/input)×100
if u get confused which way input and output should go, remember the smaller value is always output and it's above in the fraction, then only it's possible to get a efficiency lower than 100.

7 0

2 years ago

Read 2 more answers

Help with 5 and the question below. BRAINLIEST FOR THE CORRECT ANSWER! Urgent Physics help!

krok68 [10]

Sound level at distance of 15 m is given as 20 dB

so intensity at this distance is given as

$L = 10 Log\frac{I}{I_0}$

$20 = 10 Log{I}{10^{-12}}$

$I_1 = 10^{-10}W/m^2$

now if we move closer to some some distance the sound level is now 50 dB

now the intensity is given as

$L = 10 Log\frac{I}{I_0}$

$50 = 10Log\frac{I}{10^{-12}}$

$I_2 = 10^{-7}W/m^2$

now we know that

$\frac{I_1}{I_2} = \frac{r_2^2}{r_1^2}$

$\frac{10^{-10}}{10^{-7}} = \frac{r_2^2}{15^2}$

$r_2 = 47 cm$

so now the distance from friend must be 47 cm

8 0

2 years ago

The tides on earth are caused mainly by earths gravitational interactions with which of the following?

Llana [10]

<span>The tides on earth are caused mainly by earths gravitational interactions with the sun and the moon.</span>

3 0

2 years ago

As part of a safety investigation, two 1900 kg cars traveling at 20 m/s are crashed into different barriers. Part A Find the ave

DedPeter [7]

Answer:

- $29.2\times 10^{3} N$

Explanation:

We are given that

Mass of cars= m=1900 kg

Initial speed of car=u=20 m/s

Final speed of car=v=0

Time= $\Delta t$ =1.3 s

We have to find the average force exerted on the car.

Average force= $\frac{change\;in\;momentum}{\Delta t}$

$F_{avg}=\frac{mv-mu}{1.3}$

$F_{avg}=\frac{1900(0)-1900(20)}{1.3}$

$F_{avg}=\frac{-38000}{1.3}=-29.2\times 10^{3} N$

Hence, the average force exerted on the car that hits a line of water barrels=- $29.2\times 10^{3} N$

8 0

3 years ago