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Alik [6]
2 years ago
11

How long will it take a plane to fly 1256km if it travels 500km/hr?

Physics
1 answer:
expeople1 [14]2 years ago
4 0

Answer:

<h3>The answer is 2.51 s</h3>

Explanation:

The time taken can be found by using the formula

t =  \frac{d}{v}  \\

d is the distance

v is the velocity

From the question we have

t =  \frac{1256}{500}  \\  = 2.512

We have the final answer as

<h3>2.51 s</h3>

Hope this helps you

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ExtremeBDS [4]

Answer:

50m

   

Explanation:

Given parameters:

Initial velocity  = 20m/s

Acceleration  = 4m/s²

Time  = 10s

Unknown:

Distance traveled by the rocket  = ?

Solution:

To solve this problem use the expression below;

   

     v² = u² + 2as

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance

  final velocity = 0

 Insert the parameters and solve;

  0²  = 20² + 2 x 4 x s

   -400  = 8s

         s  = 50m

   Disregard the negative sign because distance cannot be negative.

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2 years ago
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Temka [501]

Answer:3,600 Newtons

Explanation:

The net force acting on the car is

3×10^3squared

Newtons.

Force is defined as the product of the mass of the body and its aaceleration,⇒F=ma

Substituting the above given values we get,F=(1500kg) (2.0m /s^2 squared)=3000 N=3×10^3 squared N.

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7 0
3 years ago
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attashe74 [19]

Answer:

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5 0
3 years ago
A car accelerates from rest to a speed of 8 m/s over a distance of 16 m. What is the acceleration of the car?
Marina CMI [18]
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5 0
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An optical disk drive in your computer can spin a disk up to 10,000 rpm (about 1045 rad/s 1045 rad/s ). If a particular disk is
Scilla [17]

Answer:

The magnitude of the average angular acceleration of the disk is 4139.74\ rad/s^2.

Explanation:

Given that,

Angular velocity, \omega_i=968.7\ rad/s

The disk comes to rest, \omega_i=0

Time, t = 0.234 s

We need to find the magnitude of the average angular acceleration of the disk. It is given by change in angular velocity per unit time. So,

\alpha =\dfrac{\omega f}{t}\\\\\alpha =\dfrac{968.7\ rad/s}{0.234\ s}\\\\\alpha =4139.74\ rad/s^2

So, the magnitude of the average angular acceleration of the disk is 4139.74\ rad/s^2.

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3 years ago
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