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2 years ago

Members of the student council have been asked by their

Engineering

1 answer:

kobusy [5.1K]2 years ago

7 0

Answer:

How to plan? Achievable goals. Expected timetable. Slogan. How to execute the presentation. How to attract the audience. Et cetera

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Annealing is a process by which steel is reheated and then cooled to make it less brittle. Consider the reheat stage for a 100-m

zvonat [6]

Answer:

T = 858.25 s

Explanation:

Given data:

Reheat stage for a 100-mm-thick steel plate ( 7830 kg/m3, c 550 J/kg K, k 48 W/m K),

initial uniform temperature ( Ti ) = 200 c

Final temperature = 550 c

convection coefficient = 250 w/m^2 k

products combustion temp = 800 c

calculate how long the plate should be left in the furnace ( to attain 550 c )

first calculate/determine the Fourier series Number ( Fo )

$\frac{T_{0}-T_{x} }{T_{1}-T_{x} } = C_{1} e^{(-0.4888^{2}*Fo )}$

= 0.4167 = $1.0396e^{-0.4888*Fo}$

therefore Fo = 3.8264

Now determine how long the plate should be left in the furnace

Fo = $(\frac{k}{pc_{p} } ) ( \frac{t}{(L/2)^2} )$

k = 48

p = 7830

L = 0.1

Input the values into the relation and make t subject of the formula

hence t = 858.25 s

8 0

2 years ago

We would like to measure the density (p) of an ideal gas. We know the ideal gas law provides p= , where P represents pressure, R

Nostrana [21]

Answer: =

Explanation:

= P / (R * T) P- Pressure, R=287.058, T- temperature

From the given that

Sample mean(pressure) = 120300 Pa

Standard deviation (pressure) = 6600 Pa

Sample mean(temperature) = 340K

Standard deviation(temperature) = 8K

To calculate the Density;

Maximum pressure = Sample mean(pressure) + standard deviation (pressure) = 120300+6600 = 126900 Pa

Minimum pressure = Sample mean (pressure) - standard deviation (pressure)= 120300-6600 = 113700 Pa

Maximum temperature = Sample mean (temperature) + standard deviation (temperature) = 340+8 = 348K

Minimum temperature = Sample mean (temperature) - standerd deviation (temperature) = 340-8 = 332K

So now to calculate the density:

Maximum Density= Pressure (max)/(R*Temperature (min))= 126900/(287.058*332)= 1.331

Minimum density=Pressure(min)/(R*Temperature (max))= 113700/(287.058*348)= 1.138

Average density= (density (max)+ density (min))/2= (1.331+1.138)/2= 1.2345

cheers i hope this helps

5 0

2 years ago

A sample of cast iron with .35 wt%C is slow cooled from 1500C to room temperature. What is the fraction of proeutectoid Cementit

Marizza181 [45]

Answer:

So the fraction of proeutectoid cementite is 44.3%

Explanation:

Given that

cast iron with 0.35 % wtC and we have to find out fraction of proeutectoid cementite phase when cooled from 1500 C to room temperature.

We know that

Fraction of proeutectoid cementite phase gievn as

${w_p}'=\dfrac{{C_o}'-0.022}{0.74}$

Now by putting the values

${w_p}'=\dfrac{0.35-0.022}{0.74}$

${w_p}'=0.443$

So the fraction of proeutectoid cementite is 44.3%

6 0

2 years ago

Water at 98 F flows in a pipe 4 inches in diamter and 870 feet in length at a rate of 260 gallons per minute (GPM). What is the

Basile [38]

Answer:

Reynolds number is 293068.43.

Explanation:

Step1

Given:

Water temperature is 98 °F.

Diameter of the pipe is 4 in

Length of the pipe is 870 feet.

Flow rate of water is 260 gallons per minute.

Calculation:

Step2

Water kinematic viscosity at temperature 98 F is $7.55\times10^{-6}$ ft²/s.

Find the velocity of the water as follows:

Q=AV

$Q=\frac{\pi}{4}D^{2}V$

$(260 gal/min)(\frac{0.00222801 ft^{3}/s}{1 gal/min})=\frac{\pi}{4}(\frac{4}{12})^{2}V$

V=6.638 ft/s

Step3

Expression for Reynolds number is given as follows:

$Re=\frac{vd}{\nu}$

Here, v is velocity, $\nu$ is kinematic viscosity, d is diameter and Re is Reynolds number.

Substitute the values in the above equation as follows:

$Re=\frac{vd}{\nu}$

$Re=\frac{6.638\times(4in)(\frac{1ft}{12in})}{7.55\times10^{-6}}$

Re= 293068.43

Thus, the Reynolds number is 293068.43.

7 0

2 years ago

Name all the Airforce RANKS? Please and thank you!

Helen [10]

Answer:

1) Airman (AMN)

2) Airman First class (A1C)

3) Senior Airman (SrA)

4) Staff sergeant (SSgt)

5) Tech. Sergeant (TSgt)

6) Master sergeant (MSgt)

7) First sergeant (E-7)

8) Senior Master Sergeant (SMSgt)

9) First Sergeant (E-8)

10) Chief Master Sergeant (CMSgt)

11) First sergeant (E-9

12) Command chief Master Sergeant (CCM)

13) Chief Master Sergeant Of The Airforce (CMSAF

7 0

2 years ago

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