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aliina [53]
3 years ago
10

This manometer is used to measure the difference in water level between the two tanks.

Engineering
1 answer:
SpyIntel [72]3 years ago
3 0

Answer:

a) True

Explanation:

hope it helps u

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9
Alex17521 [72]

Answer:

do it if it's Sunday why are you like this

6 0
3 years ago
Carbon dioxide (CO2) expands isothermally at steady state with no irreversibilities through a turbine from 10 bar, 500 K to 2 ba
xenn [34]

Answer:

The answer to the question above is = 152.02 KJ/Kg

Explanation:

Given:

Temperature at first state, (T1)= 500k

Temperature at second state, (T2)= 500k

The above explains an isothermal process as a thermodynamic process,in which the temperature of the system remains constant

Pressure at first state, (p1) = 10 bar

Pressure at second state, (p2) = 2 bar

The heat transfer=

Qrev/m= T x [s(T2) - s(T1) - R ㏑ (p2 ÷ p1)]

Isothermal means the temperature does not change, while Expansion means the volume has increased.

For the internal isothermal process:

Qrev/m=  T x [- R ㏑ (p2 ÷ p1)]

= 500 x  - (8.314 ÷ 44.01) x In (2 ÷ 10) = 152.02 KJ/Kg

Energy equation at turbine is for the internally reversible isothermal process is:

Q-w = m [( (V2²- V1²) ÷ 2) + g ( Z2 - Z1)]

where w= the most efficient work possible in  J

Neglecting the effect of both potential and kinetic energy

(w/ m) = Qrev/ m

= 152.02 KJ/Kg

4 0
3 years ago
The title block generally contains ________.
gavmur [86]
B the mechanical plans
7 0
3 years ago
How many different powerball combinations are there
svlad2 [7]
Answer:





There 11,238,513 different Powerball
4 0
2 years ago
A 0.25" diameter A36 steel rivet connects two 1" wide by .25" thick 6061-T6 Al strips in a single lap shear joint. The shear str
just olya [345]

Answer:

Option B

1025 psi

Explanation:

In a single shear, the shear area is \frac {\pi d^{2}}{4}=\frac {\pi 0.25^{2}}{4}

The shear strength=0.58\sigma_y and in this case \sigma_y=36 000 psi

Shear strength=\frac {Load}{Shear area} hence making load the subject then

Load=Shear area X Shear strength

Load=\frac {\pi 0.25^{2}}{4} \times 0.58\times 36000\approx 1025 psi

3 0
3 years ago
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