This manometer is used to measure the difference in water level between the two tanks.
1 answer:
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Answer:
a) aA = - 13.33 mm/s²
aB = - 20 mm/s²
b) aD = - 13.33 mm/s²
c) vB = 70 mm/s
d) xB = 440 mm
Explanation:
Given
The initial speed of B is: v₀B = 150 mm/s
Distance moved by A is: xA = 240 mm
Velocity of A is: vA = 60 mm/s
Assuming:
Displacement of blocks are denoted by:
A = xA
B = xB
C = xC
D = xD
From the pic shown, the total length of the cable is:
xB + (xB - xA) + 2*(d - xA) = L
⇒ 2*xB - 3*xA = L - 2*d
where L - 2*d is constant. Differentiating the above equation with respect to time:
d(2*xB)/dt - d(3*xA)/dt = 0
⇒ 2*vB - 3*vA = 0 (i)
Substituting in equation (i)
2*(150 mm/s) - 3*vA = 0
⇒ v₀A = 100 mm/s (initial speed of A)
Then, we use the equation
vA² = v₀A² + 2*aA*xA
Substituting the values in above equation:
(60 mm/s)² = (100 mm/s)² + 2*aA*(240 mm)
⇒ aA = - 13.33 mm/s²
If 2*vB - 3*vA = 0
Differentiating the above equation with respect to time:
d(2*vB)/dt - d(3*vA)/dt = 0
⇒ 2*aB - 3*aA = 0 (ii)
Substituting in equation (ii)
2*aB - 3*(- 13.33 mm/s²) = 0
⇒ aB = - 20 mm/s²
b) From the pic shown,
xD - xA = constant
If we apply
d(xD)/dt - d(xA)/dt = 0
⇒ vD - vA = 0
then
d(vD)/dt - d(vA)/dt = 0
⇒ aD - aA = 0
⇒ aD = aA = - 13.33 mm/s²
c) We use the formula
vB = v₀B + aB*t
Substituting the values in above equation:
vB = 150 mm/s + (- 20 mm/s²)*(4 s)
⇒ vB = 70 mm/s
d) We apply the equation
xB = v₀B*t + 0.5*aB*t²
Substituting the values in above equation:
xB = (150 mm/s)*(4 s) + 0.5*(- 20 mm/s²)*(4 s)²
⇒ xB = 440 mm
Answer:
See explaination
Explanation:
Lets first consider the term Isentropic efficiency. The isentropic efficiency of a compressor or pump is defined as the ratio of the work input to an isentropic process, to the work input to the actual process between the same inlet and exit pressures. IN practice, compressors are intentionally cooled to minimize the work input.
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