Answer:
The answer is V = √2FD ÷ CD × PA
Explanation:
FD = CD × PV²A ÷ 2
V² = 2FD ÷ CD × PA
V = √2FD ÷ CD × PA
Thus, The value of V is V = √2FD ÷ CD × PA
<u>-TheUnknownScientist 72</u>
Explanation:
a). <u>Operational Performance</u>
It is defined as the parameter that describes the percentage of accuracy of performing an operation or carrying out an activity.
b). <u>Salvage externalities</u>
Salvage in Life cycle cost analysis is a process of estimating the value of the remaining assets in the organisation,.
c). <u>Value Vs Risk</u>
When we take risk in doing any activity we know the value of accomplising the activity. So value relates directly with risk. When the value of a certain task is high, the risk involve in it is also high.
d). <u>Initial expenditure</u>
Initial expenditure is nothing but the cost involve in starting a particular acitvity or task at the starting phase.
e). <u>Maintenance implications</u>
It lays emphasis in maintaining the cost of every possible parameters that are involve in the activity. It includes labour, machines, positions, energy, facilities, etc.
Answer:
Total saving would be of 36.917 $\yr
Explanation:
Given Data:
Degree F
Degree F
A = 30 ft^2
%
Heat loss before previous final value 
= 360 Btu/hr
Heat loss after new value
saving would be 
= 616.1782 kw hr/yr
$
= 36.917 $\yr
