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3 years ago

Compare the temperature dependence of Nabarro-Herring and Coble creep. Which is more temperature-sensitive

1 answer:

7 0

Lower temperatures favor Coble creep and higher temperatures favor Nabbaro–Herring creep because the activation energy for vacancy diffusion within the lattice is typically larger than that along the grain boundaries, thus lattice diffusion slows down relative to grain boundary diffusion with decreasing temperature.

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a circular pile, 19 m long is driven into a homogeneous sand layer. The piles width is 0.5 m. The standard penetration resistanc

Elena L [17]

Answer:

Point force (Qp) = 704 kn/m²

Explanation:

Given:

length = 19 m

Width = 0.5 m

fs = 4

Vicinity of the pile = 25

Find:

Point force (Qp)

Computation:

Point force (Qp) = fs²(l+v)

Point force (Qp) = 4²(25+19)

Point force (Qp) = 16(44)

Point force (Qp) = 704 kn/m²

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3 years ago

Find the True statement

dmitriy555 [2]

Answer:

Option A is correct ( Stress relaxation is time- and temperature-dependent).

Explanation:

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3 years ago

Read 2 more answers

All of the following safety tips are true EXCEPT Select one: a. It is not acceptable to handle broken glass with your bare hands

netineya [11]

Answer:

Explanation:

B. you would grab the plug closest to the outlet

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3 years ago

Eight energy corporations made plans to increase their combined spending on efficiency programs to $50 million per year for the

tangare [24]

Answer:

F=531831381

Explanation:

There are two ways of doing this question:

1) By Formula

2) By Using Compound interest Table

By Formula:

$F=A*\frac{(1+i)^{n}-1}{i}$

Where:

F is future value

A is annual amount per year

i is interest rate

n is number of years

$F=50 million*\frac{(1+0.08)^{8}-1}{0.08}$

F=531831381

By Using Compound interest Table:

F=A(F/A,i,n)

From Table F/A at i=8% and n=8 is 10.6366

F=50000000*(10.6366)

F=531830000≅531831381

The difference in two answers is due to decimal points if you take value from table to greater decimal points you will get the exact answer as by using formula.

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3 years ago

In a Rankine cycle, superheated steam that enters the turbine at 1273.15 K and 1.8 MPa is then expanded to a vapor at 0.1 MPa. W

GrogVix [38]

Answer:

The shaft work generated per kilogram is $-1.3 \frac{MJ}{kg}$