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3 years ago

Describe the energy transformations that occur from the time a skydiver jumps out of a plane until landing on the ground.

2 answers:

7 0

I think, the skydiver has maximum potential energy before jumping. However, as the skydiver jumps and decreases in height, he increases the velocity. Thus, as soon as the skydiver has jumped he is experiencing kinetic energy. The velocity of the skydiver increases as he moves down wards due to gravitational acceleration until he attains terminal velocity.

icang [17]3 years ago

4 0

Sample Response:<span> Before jumping from the plane, the skydiver has potential energy. When the skydiver jumps, the potential energy is transformed into kinetic energy, which increases until the skydiver reaches terminal velocity. Potential energy is then transformed into thermal energy.</span>

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I'm writing a story about Granny using old-fashioned laundry bluing to freshen dingy yellow clothes. I would like to explain WHY

Katena32 [7]

By combining blue with yellow light is like combining blue light with red and green light. The result of combining these three primary colors of light is to produce white light.

<h3>What is laundry bluing ?</h3>

Laundry bluing is a product adds a trace amount of blue dye to white fabric during laundering to improve its appearance.

Bluing products in higher concentrations can darken jeans and other blue cloth.

The blue overpowered the yellow to reflect white (at least the appearance of white to the human eye).

Blue and yellow are complementary colors that combine to reflect white, Fabrics.

Here,

Yellow light is a combination of red and green light. So combining blue with yellow light is like combining blue light with red and green light. The result of combining these three primary colors of light is to produce white light.

Learn more about White light here:brainly.com/question/16317768

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2 years ago

The leg's force forward on the foot= 500N

Anna11 [10]

There's so much going on here, in a short period of time.

<u>Before the kick</u>, as the foot swings toward the ball . . .

-- The net force on the ball is zero. That's why it just lays there and
does not accelerate in any direction.

-- The net force on the foot is 500N, originating in the leg, causing it to
accelerate toward the ball.

<u>During the kick</u> ... the 0.1 second or so that the foot is in contact with the ball ...

-- The net force on the ball is 500N. That's what makes it accelerate from
just laying there to taking off on a high arc.

-- The net force on the foot is zero ... 500N from the leg, pointing forward,
and 500N as the reaction force from the ball, pointing backward.

That's how the leg's speed remains constant ... creating a dent in the ball
until the ball accelerates to match the speed of the foot, and then drawing
out of the dent, as the ball accelerates to exceed the speed of the foot and
draw away from it.

5 0

3 years ago

When I double displacement reaction takes place, one of the products must be_______.

sattari [20]

Answer:

the answer would be Salt

Explanation:

3 0

2 years ago

Read 2 more answers

R S ( M ) = 2 G M c 2 , where G is the gravitational constant and c is the speed of light. It is okay if you do not follow the d

padilas [110]

The provided question's answer is "Schwarzschild radius".

The conversion factor between mass and energy is the speed of light squared.

GM/r stands for gravitational potential energy, also known as energy per unit mass.

GM/rc² then has "mass per unit mass" units. In other words, as mass/mass splits out in a dimensional analysis, "dimensionless per unit."

The derivation yields a formula for time or space coordinate ratios requiring sqrt(1 - 2GM/rc²). This number becomes 0 when r=2GM/c2, or the formula becomes infinite if in the denominator. However, there is no justification for using c² as a conversion factor there. Consider the initial expression sqrt(1 - 2GM/rc²).

Assume that m is used as the test particle's mass instead of 1. Then you have sqrt(m - 2GMm/rc² and mass units. This expression denotes that the rest energy of the test mass m you introduced into the gravitational field is "gone" at that radius.

The 2 would be absent if the gravitational field were Newtonian. However, at the event horizon, Einstein gravity is slightly stronger than Newton gravity, resulting in the factor 2 in qualitative terms.

So, the given equation is of Schwarzschild radius.

Learn more about Schwarzschild radius here:

brainly.com/question/12647190

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3 0

2 years ago

Question 5

goldfiish [28.3K]

Answer:

Explanation:

5 0

3 years ago