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nydimaria [60]
3 years ago
9

Why does a balloon stick to a wall questions and problems answers?

Physics
1 answer:
Akimi4 [234]3 years ago
7 0
<span>The reason that the balloon will stick to the wall is because the negative charges in the balloon will make the electrons in the wall move to the other side of their atoms and this leaves the surface of the wall positively charged.</span>
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A light bulb and a solenoid are connected in series to a battery. An irod rod is thrust rapidly into the solenoid and later rapi
Ivanshal [37]

Answer:

3) Dims in, Brightens out

Explanation:

The relationship between the inductance of a coil and the current is inverse.

As the rod is thrusted into the solenoid, the inductance increases, which in turn decreases the current and the bulb gets dimmer. This is also because some magnetic force is drawn away from the solenoid and the battery.

When the rod is removed, the inductance of the solenoid decreases, the current increases, and the bulb becomes brighter.

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3 years ago
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How did ALS impact Stephen Hawking?
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Answer:

Professor Hawking had just turned 21 when he was diagnosed with a very rare slow-progressing form of ALS, a form of motor neurone disease (MND). He was at the end of his time at Oxford when he started to notice early signs of his disease. He was getting more clumsy and fell over several times without knowing why.

Explanation:

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3 years ago
Which property of light remains unchanged when it enters a different medium?
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The FREQUENCY of light remains unchanged once it leaves the source.
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3 years ago
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Sadi Carnot came up with a hypothetical heat engine that had the maximum possible efficiency. What discovery did Carnot make tha
otez555 [7]
The discovery which Carnot made was that THE DIFFERENCE IN THE TEMPERATURES BETWEEN THE HOT AND THE COLD RESERVOIRS DETERMINE HOW WELL A HEAT ENGINE WOULD WORK.
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3 years ago
Which of the physical variables listed below will change when you change the area of the capacitor plates (while keeping the bat
RSB [31]

Answer:

a. Capacitance

b. Charge on the plates  

e. Energy stored in the capacitor

Explanation:

Let A be the area of the capacitor plate

The capacitance of a capacitor is given as;

C = \frac{Q}{V} = \frac{\epsilon _0 A}{d} \\\\

where;

V is the potential difference between the plates

The charge on the plates is given as;

Q = \frac{V\epsilon _0 A}{d}

The energy stored in the capacitor is given as;

E = \frac{1}{2} CV^2\\\\E = \frac{1}{2} (\frac{\epsilon _0 A}{d} )V^2

Thus, the physical variables listed that will change include;

a. Capacitance

b. Charge on the plates  

e. Energy stored in the capacitor

3 0
3 years ago
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