Answer:

Explanation:
We are given that a parallel- plate capacitor is charged to a potential difference V and then disconnected from the voltage source.
1 m =100 cm
Surface area =S=


We have to find the charge Q on the positive plates of the capacitor.
V=Initial voltage between plates
d=Initial distance between plates
Initial Capacitance of capacitor

Capacitance of capacitor after moving plates


Potential difference between plates after moving








Hence, the charge on positive plate of capacitor=
Answer:
Silver is a malleable and ductile metal having atomic number 47 and symbol Ag. Gold on the hand has atomic number 79 and symbol Au. It is also ductile and malleable. Both are soft and lustrous in nature. Both are transition metals.
Bronze is an alloy of majority of copper and some amount of tin. Formation of alloy enhances the properties of the metal and its industrial use. Bronze is harder than copper and easily fusible and easy to cast. It is resists corrosion.
Silver and gold have different atomic numbers, different colors. Both are transition elements where as Bronze is an alloy.
Answer:
This might be easier with the textbook
Answer:
135degrees
Explanation:
Given that a vector starts at the point (0.0) and ends at (3,-3)
y component value = -3
x component value = 3
angle of the displacement theta = arctan(y/x)
theta = arctan(-3/3)
theta = arctan (-1)
theta = -45degrees
Since tan is negative in the second quadrant
theta = 180 - 45
theta = 135degrees
Hence the angle of the displacement is 135degrees