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3 years ago

What is a electron orbit?

2 answers:

7 0

Electrons occupy shells around the nucleus of an atom. Electrons move in every direction, but they are limited to their own area, or the orbit that the electron follows, which is what we call shells. Within each shell, there are sub-shells. ... Orbitals are regions within an atom that the electron will most likely occupy.

Advocard [28]3 years ago

5 0

the path of an electron around the nucleus of an atom

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If a book is knocked off a desk that is .75 m tall at a rate of 2.0 m/s, how far away from the desk does it fall

ANEK [815]

Answer: 0.8 m

Explanation:

In the vertical direction, the speed is zero, u = 0.

Distance covered in the vertical direction, s = 0.75 m.

The book would fall with acceleration due to gravity in the vertical direction, a = g = 9.8 m/s²

From the equation of motion,

s = u t + 0.5 a t²

Substituting the above values, we will find out the time taken for the book to hit the ground.

⇒0.75 m=0+0.5×9.8 m/s²×t²

⇒t = √0.153 = 0.39 s ≈ 0.40 s

Now, the horizontal distance covered,

d = v×t ⇒d= 2.0 m/s × 0.40 s =0.8 m

Hence, the book falls 0.8 m away from the desk.

7 0

3 years ago

What is the velocity of an object that has a mass of 2.5 kilogram and a momentum of 1,000 kg·m/sec?

nadezda [96]

V = p / m

V = 1000 / 2.5

V = 400 m/s

hope this helps!

7 0

3 years ago

If the organ pipe is cut in half, what is the new fundamental frequency? if the organ pipe is cut in half, what is the new funda

bogdanovich [222]

The frequency for a fundamental pipe is given as:

f = v/4L

L is equal to the length of the pipe

Since L = Lo/2 where Lo is the original length of the pipe, the new frequency would be:

f = (v/4)/(Lo/2)

f = 2 (v/4Lo)

Since v/4Lo = fo, therefore:

f = 2 fo

8 0

4 years ago

A 500-kg roller coaster car travels with some initial velocity along a track that is 5 m above the ground. The car goes down a s

LUCKY_DIMON [66]

Answer:

12m/s

Explanation:

4 0

3 years ago

The height of a cone is increasing at a rate of 10 cm/sec and its radius is decreasing so that its volume remains constant. How

ki77a [65]

Answer:

dr/dt = -2 cm/s.

Explanation:

The volume of a cone is given by:

$V=\frac{1}{3} \pi r^{2}h$ (1)

r is the radius
h is the height

Let's take the derivative with respect to time in each side of (1).

$\frac{dV}{dt}=\frac{1}{3} \pi \frac{d}{dt}(r^{2}h)=\frac{1}{3} \pi \left(2r\frac{dr}{dt}h+r^{2}\frac{dh}{dt} \right)$ (2)

We know that:

dh/dt = 10 cm / s (rate increasing of height)
dV/dt = 0 (constant volume means no variation with respect of time)
r = 4 cm
h = 10 cm

We can calculate how fast is the radius changing using the above information.

$0=\frac{1}{3} \pi \left( 2\cdot 4\cdot \frac{dr}{dt} \cdot 10 + 4^{2}\cdot 10)\right$

Therefore dr/dt will be:

$\frac{dr}{dt}=-\frac{160}{80}=-2 cm/s$

The minus signs means that r is decreasing.

I hope it helps you!

6 0

3 years ago