Something must be wrong in the data you have, since this is basic using of linear motion's formulas.
vf=v0+at. Where vf= final velocity; v0= initial velocity, a=acceleration and t=time.
If the rocket is initially at rest, v0=0. Therefore vf=at. Plugging numbers in gives 445=99*4.5, However
445≠445.5.
Check it and then calculate the distance from x=a*t^2.
Answer:
Increases.
Explanation:
The electric potential increases when the two positive charges of same magnitude bring close to one charge to another because there is repulsive force between them due to same charge and when the two opposite charges move away from each other, the potential energy decreases. When two opposite charges are brought closer together, electric potential energy decreases while on the other hand, when we move opposite charges apart from each other than the work done against the attractive force that leads to an increase in electric potential energy.
Stretch all with a weight.
e.g. stretch 1, 2 and 3 with a 10g weight. if does not break, proceed with a 20g, the 30g consecutively. last one which holds the heaviest weight is the most durable one.
The speed of spaceship moving is 2.4 x 10^8 m/s
As from the given data, the clock in a spaceship is observed to run at a speed of 3/5 of a similar clock that rest on the earth is
T/T° = 3/5
The expression for the time dilation is given by
T = γT°
γ = T/T°
γ = 1/√1 - v^2/c^2 is time dilation
Substituting the values in the above equation as,
γ = T/T°
5/3 = 1/√1 - v^2/c^2
v^2/c^2 = 16/25
v = 0.8 c
v = 0.8 x 3 x 10^8 m/s
v = 2.4 x 10^8 m/s
Hence, speed of spaceship moving is 2.4 x 10^8 m/s
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