A particle is to move in an xy plane, clockwise around the origin as seen from the positive side of the z axis. In unit-vector n
otation, what torque acts on the particle if the magnitude of its angular momentum about the origin is (a) 4.0 kg ⋅ m2/s, (b) 4.0t2 kg ⋅ m2/s, (c) 4.0 √ t kg ⋅ m 2 / s and (d) 4.0/t2 kg ⋅ m2/s?
1 answer:
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Answer:
P = 96 J
Explanation:
Given that,
Weight of the book, W = mg = 8 N
It is placed at a height of 12 m
We need to find the potential energy of the book. The potential energy of an object is given by the formula as follows :
E = mgh
mg = Weight
So, the potential energy of the book is 96 J.
Answer:
The magnitude of the force the light beam exerts on the man is 5.9 x 10⁻⁵N
(b) the force the light beam exerts is much too small to be felt by the man.
Explanation:
Given;
cross-sectional area of the man, A = 0.500m²
intensity of light, I = 35.5kW/m²
If all the incident light were absorbed, the pressure of the incident light on the man can be calculated as follows;
P = I/c
where;
P is the pressure of the incident light
I is the intensity of the incident light
c is the speed of light
F = PA
where;
F is the force of the incident light on the man
P is the pressure of the incident light on the man
A is the cross-sectional area of the man
F = 1.18 x 10⁻⁴ x 0.5 = 5.9 x 10⁻⁵ N
The magnitude of the force the light beam exerts on the man is 5.9 x 10⁻⁵ N
Therefore, the force the light beam exerts is much too small to be felt by the man.