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garri49 [273]
3 years ago
14

A railroad freight car, mass 15 000 kg, is allowed to coast along a level track at a speed of 2.0 m/s. It collides and couples w

ith a 50 000-kg loaded second car, initially at rest and with brakes released. What percentage of the initial kinetic energy of the 15 000-kg car is preserved in the two-coupled cars after collision
Physics
1 answer:
baherus [9]3 years ago
7 0

Answer:

23.0760769 %

Explanation:

m_1 = Mass of freight car = 15000 kg

m_2 = Mass of second car = 50000 kg

v_1 = Velocity of freight car = 2 m/s

v_2 = Velocity of second car = 0

v = Combined mass velocity

As the linear momentum of the system is conserved we have

m_1v_1+m_2v_2=(m_1+m_2)v\\\Rightarrow v=\dfrac{m_1v_1+m_2v_2}{m_1+m_2}\\\Rightarrow v=\dfrac{15000\times 2+50000\times 0}{15000+50000}\\\Rightarrow v=0.46153\ m/s

The initial kinetic energy

K_i=\dfrac{1}{2}15000\times 2^2\\\Rightarrow K_i=30000\ J

Final kinetic energy

K_f=\dfrac{1}{2}(15000+50000)\times 0.46153^2\\\Rightarrow K_f=6922.82307\ J

The percentage is given by

\dfrac{6922.82307}{30000}\times 100=23.0760769\ \%

The change in percentage of initial kinetic energy is 23.0760769 %

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