Question

How far from a 10 µC point charge will the potential be 1000 V?

Answer 1

Answer:

• Point charge (Q) = 10 μC = 10 × 10⁻⁶ C

• Potential (V) = 1000 V

• Distance (r) = ?

$\implies V = \dfrac{KQ}{r}$

$\implies r= \dfrac{KQ}{V}$

$\implies r= \dfrac{9 \times {10}^{9} \times 10 \times {10}^{ - 6} }{1000}$

$\implies r= \dfrac{90 \times {10}^{3} }{1000}$

$\implies r= \dfrac{90 \times {10}^{3} }{ {10}^{3} }$

$\implies r= 90 \times {10}^{3} \times {10}^{ - 3}$

$\implies\bf r= 90\:m$

Hence,the option B) 90 m is the correct answer.