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Setler [38]
3 years ago
12

A ball is dropped from a height of 20m and renounce with the velocity which is 3/4 of d velocity with which it hits the ground.

What is d tym interval btw the first and second bounces​
Physics
1 answer:
Mashutka [201]3 years ago
3 0

Answer:

1.73 seconds

Explanation:

The velocity the ball first hits the ground with is:

v² = v₀² + 2aΔx

v² = (0 m/s)² + 2 (-10 m/s²) (-20 m)

v = -20 m/s

The velocity it rebounds with is 3/4 of that in the opposite direction, or 15 m/s.

The time it takes to return to the ground is:

Δx = v₀ t + ½ at²

0 = (15 m/s) t + ½ (-10 m/s²) t²

0 = t (15 − 5t²)

t = √3

t ≈ 1.73 seconds

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Explanation:

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F_1=\dfrac{0.145\ kg\times 44\ m/s}{0.0022\ s}

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Flura [38]
A.)

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6 0
3 years ago
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What would happen to mass and accelaration if the force on an object increases?? please help.
kozerog [31]
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Vadim26 [7]

Answer:

The correct answer to the question is

B. It always decreases

Explanation:

To solve the question, we note that the foce of gravity is given by

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