Answer:
a) τ₁ = 660 N m, b) τ’= 686 N m, c) F = 623.6 N
Explanation:
a) For this exercise let's use the concepts of torque and rotational balance.
For this we set a reference system at the base and assuming that the counterclockwise rotations are positive
where the force F = 600 N, the distance to the axis is x = 1.1 m, the mass of the system m = 70g and the weight is placed at the point of the center of gravity x_{cm} = -1.0 m
The torque at the front is
τ₁ = F x
τ₁ = 600 1.1
τ₁ = 660 N m
b) let's write the rotational equilibrium condition
∑ τ = 0
τ'- W x_{cm} = 0
τ ’= mg x_{cm}
τ’= 70 9.8 1.0
τ’= 686 N m
c) the greatest force Matt can apply
τ’= F x
F = τ’/ x
F = 686 / 1.1
F = 623.6 N
Answer:
f Homework: Creating and Solving Linear Equations to Model Real World Problems Part I
he document will
1) Use the story below about Sanjeet and his friends' end-of-season basketball statistics to answer the
questions that follow.
Story
Points Scored
Terrence's points:
Sanjeet and his teanit members were looking
Sanjeet's points:
Cole's points:
at the total points scored by each player
during the season. Sanjeet scored twice ay
many pointy ay Terrence. Cole scored 12
more points than Sanjeet. Together the boys
scored 992 points during the season. How
many points did each boy score?
Equation:
Explanation:
Please Mark Me As A Brainliest
1. The answer is gravity. This is the power that draws two bodies to each other, the force that causes objects to drop toward the ground and the planets to orbit the sun. The huger an object is, the tougher it’s gravitational pull.
2. The answer is free fall. This is any motion of a body where gravity is the only power performing upon it. In the setting of general relativity, where gravitation is lessen to a space-time curvature, a body in free fall has no power performing on it
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