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4 years ago

A ball falls from the top of a building. As it falls, its speed increases. Which type of energy is the ball gaining as it falls?

Physics

1 answer:

Elina [12.6K]4 years ago

5 0

<h2>Hello!</h2>

The answer is: B. Kinetic energy

Since the ball is falling, speed increases because the gravity acceleration is acting. When speed increases, the kinetic energy increases too, so the ball is gaining kinetic energy.

The gravity acceleration is equal to $9.81\frac{m}{s^{2}}$ , it means that when falling, the ball will increase it's speed 9.81m every second.

We can calculate the kinetic energy by using the following formula:

$KE=\frac{1}{2}*m*v^{2}$

Where:

$m=mass\\v=velocity$

Have a nice day!

<h2 />

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The string constrains the rotational and translational motion of the falling cylinder, given that it doesn't slip. what is the r

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3 years ago

The radius of a lead atom is 175 pm. how many lead atoms would have to be laid side by side to span a distance of 6.11 mm?

podryga [215]

The number of atoms needed to be laid side by side to span a distance of 6.11 mm is 17,457,143.

<h3>What is Unit conversion?</h3>

Unit conversion is a way of converting some common units into another without changing their real value. for, example, 1 centimeter is equal to 10 mm, though the real measurement is still the same the units and numerical values have been changed.

Given that the radius of a lead atom is 175 picometers. Therefore, the radius of the lead atom in mm can be written as,

1 picometer = 10⁻⁹ millimeter

175 picometer = 175×10⁻⁹ millimeter

The radius of the lead atom = 175×10⁻⁹ millimeter

Since the atoms are needed to be arranged side by side, therefore, the diameter of one lead atom will join with the other, thus, the diameter of the lead atom is,

Diameter of lead atom = 2 × 175 × 10⁻⁹ millimeter = 350 ×10⁻⁹ millimeter

Now, let the number of lead atoms be represented by n. Therefore, the number of atoms needed to be laid side by side to span a distance of 6.11 mm is,

6.11 mm = Number of atoms × Diameter of atoms

6.11 mm = n × 350 ×10⁻⁹ mm

Solving for n,

n = 6.11 mm / 350 ×10⁻⁹ mm

n = 17,457,142.86 ≈ 17,457,143

Hence, the number of atoms needed to be laid side by side to span a distance of 6.11 mm is 17,457,143.

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The correct answer is A.

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