Some bad people will tend to forge dollar bills and make fake bills, giving them to cashiers and asking for it to be split into a different amount of bills so they are given real cash and wont be caught or they will buy things, return them and be given back real money and get away with it. This is obviously a crime because it's fake.
QPOE Files
The x-ray data are stored in QPOE files (Quick Position-Ordered Events, *.qp) rather than image arrays. These are lists of photons identified by several quantities, including the position on the detector, pulse height, and arrival time. Note that, unlike IRAF images, QPOE files have no associated header file, and are always stored in the current directory, unless explicitly specified otherwise. Non-PROS IRAF tasks can also access QPOE data files in place of image arrays.
Answer:
Acceleration = (change in speed) / (time for the change)
Change in speed= (0 - 26 km/hr) = -26 km/hr
(-26 km/hr) x (1,000 m/km) x (1 hr / 3,600 sec) = -7.222 m/sec
Average acceleration = (-7.222 m/s) / (22 min x 60sec/min) = -0.00547 m/sec²
Average speed during the stopping maneuver =
(1/2) (start speed + end speed) = 13 km/hr = 3.6111 m/sec
Explanation:
Answer:
49.14 carat.
Explanation:
From the question given above, we obtained the following data:
Volume of diamond = 2.8 mL
Mass of diamond (in carat) =.?
Next, we shall determine the mass of diamond in grams (g). This can be obtained as follow:
Volume of diamond = 2.8 mL
Density of diamond = 3.51 g/mL
Mass of diamond ( in grams) =?
Density = mass /volume
3.51 = mass /2.8
Cross multiply
Mass of diamond (in g) = 3.51 × 2.8
Mass of diamond (in g) = 9.828 g
Finally, we shall Convert 9.828 g to carat. This can be obtained as follow:
1 g = 5 carat
Therefore,
9.828 g = 9.828 g /1 g × 5 carat
9.828 g = 49.14 carat.
Therefore, the mass of the diamond in carat is 49.14 carat.
Answer:
Explanation:
1 x 10²³ molecules of methane
6.02 x 10²³ molecules of methane = 1 mole of methane
10²³ molecules of methane = 1 / 6.02 moles of methane
= .166 moles .
