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Rudik [331]
2 years ago
5

Describe the hybrid orbitals used by the central atom(s) and the type(s) of bonds formed in:

Chemistry
1 answer:
ehidna [41]2 years ago
3 0

sp2 Hybridization. The valence orbitals of a central atom surrounded by three regions of electron density consist of a set of three sp2 hybrid orbitals and one unhybridized p orbital.

<h3>How do you describe hybrid orbitals?</h3>

A hybrid orbital is an orbital formed by the combination of two or more atomic orbitals. The resulting orbital has a different shape and energy than the component orbitals that form it. Hybridization is used to model molecular geometry and to explain atomic bonding.

<h3>What is the hybridization of the s atom?</h3>

The middle S atom containing the 5 valence atomic orbitals is basically hybridized to form five sp3d hybrid orbitals. In 2P-orbitals, four hybrid orbitals are overlapped and the fifth one contains a lone pair.

Learn more about hybrid orbitals here:

<h3 /><h3>brainly.com/question/11008750</h3><h3 /><h3>#SPJ4</h3>
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Write the chemical equation for the formation of HI from the single, isolated H and I atoms.
mart [117]

Answer:

H2 + I2 → 2 HI.

Explanation:

Hydrogen iodide is a diatomic gas which can be readily formed from the direct combination of the elements involved which is hydrogen and iodine. Both elements can be combined by irradiating the mixture with an electromagnetic radiation that has a wavelength which is equal to that needed to break the iodine molecule bond between the two iodine atoms

7 0
3 years ago
26. All atoms area. positively charged, with the number of protons exceeding the number of electronsb, negatively charged, with
user100 [1]
(26) All atoms area...<span><span>with the number of protons equaling the number of electrons

</span>(27) </span>The particles that are found in the nucleus of an atom are...<span> protons and neutrons.

(28) </span>As a consequence of the discovery of the nucleus by Rutherford, which model of the atom is thought to be true?...<span>Protons. electrons, and neutrons are evenly distributed throughout the volume of the atom.

(29) </span>The nucleus of an atom is...<span>the central core and is composed of protons and neutrons</span>. 
7 0
3 years ago
Given 700 ml of oxygen at 7 ºC and 106.6 kPa pressure, what volume does it take at 27ºC and 66.6 kPa pressure
o-na [289]

Answer:

The volume is 1.2L

Explanation:

Initial volume (V1) = 700mL = 0.7L

Initial temperature (T1) = 7°C = (7 + 273.15)K = 280.15K

Initial pressure = 106.6kPa = 106600Pa

Final temperature (T2) = 27°C = (27 + 273.15)K = 300.15K

Final pressure (P2) = 66.6kPa = 66600Pa

Final volume (V2) = ?

To solve this question, we need to use combined gas equation which is a combination of Boyle's law, Charles Law and pressure law.

(P1 × V1) / T1 = (P2 × V2) / T2

solve for V2 by making it the subject of formula,

P1 × V1 × T2 = P2 × V2 × T1

V2 = (P1 × V1 × T2) / (P2 × T1)

V2 = (106600 × 0.7 × 300.15) / (66600 × 280.15)

V2 = 22397193 / 18657990

V2 = 1.2L

The final volume of the gas is 1.2L

6 0
3 years ago
A 34.0 gram sample of an un-known hydrocarbon is burned in excess oxygen to form 93.5 grams of carbon dioxide and 76.5 grams of
natka813 [3]

Answer:

The answer to your question is  CH₄

Explanation:

Process

1.- Write the possible chemical reaction

                   CxHy + O₂   ⇒    CO₂  +   H₂O

2.- Calculate the amount of carbon in the reaction

Molecular mass of CO₂ = 12 + 32 = 44 g

                         44 g of CO₂ ------------------- 12 g of carbon

                         93.5 g of CO₂ ----------------  x

                          x = (93.5 x 12) / 44

                          x = 25.5 g of carbon

3.- Calculate the mass of hydrogen in the sample

Molecular mass of water = 2 + 16 = 18 g

                         18 g of water -------------   2 g of hydrogen

                          76.5 g of water --------    x g of hydrogen

                           x = (76.5 x 2) / 18

                           x = 8.5 g of hydrogen

4.- Calculate the moles of carbon and hydrogen in the sample

                           12g of carbon ------------- 1 mol

                           25.5g of carbon ---------- x

                             x = (25.5 x 1) / 12

                              x = 2.12 moles of carbon

                            1 g of hydrogen ----------- 1 mol

                            8.5 g of hydrogen -------- x

                             x = (8.5 x 1) / 1

                             x = 8.5 moles of hydrogen

5.- Divide both number of moles by the lowest number

carbon = 2.12 / 2.12 = 1

hydrogen = 2.12 = 8,5 / 2.12 = 4

6.- Write the molecular formula

                                                    CH₄                                        

7 0
3 years ago
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What is the change in the enthalpy of 120 g/s acid heated in a double pipe heat exchanger from 25°C to 100°C, if the average hea
telo118 [61]

Answer:

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Explanation:

3 0
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