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Rudik [331]
2 years ago
5

Describe the hybrid orbitals used by the central atom(s) and the type(s) of bonds formed in:

Chemistry
1 answer:
ehidna [41]2 years ago
3 0

sp2 Hybridization. The valence orbitals of a central atom surrounded by three regions of electron density consist of a set of three sp2 hybrid orbitals and one unhybridized p orbital.

<h3>How do you describe hybrid orbitals?</h3>

A hybrid orbital is an orbital formed by the combination of two or more atomic orbitals. The resulting orbital has a different shape and energy than the component orbitals that form it. Hybridization is used to model molecular geometry and to explain atomic bonding.

<h3>What is the hybridization of the s atom?</h3>

The middle S atom containing the 5 valence atomic orbitals is basically hybridized to form five sp3d hybrid orbitals. In 2P-orbitals, four hybrid orbitals are overlapped and the fifth one contains a lone pair.

Learn more about hybrid orbitals here:

<h3 /><h3>brainly.com/question/11008750</h3><h3 /><h3>#SPJ4</h3>
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4 years ago
1. In this experiment, the procedure instructs you to dissolve solid potassium hydrogen tartrate (KHT) in two different solvents
GuDViN [60]

Answer:

Water

Explanation:

Solid potassium hydrogen tartrates (KHT) is soluble in water. This is especially at room temperature.

The solvent for KHT is water.

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3 years ago
you produce 115 grams of water in a combustion reaction. how much methane do you need in grams for this to react?
lora16 [44]

Answer:about 2 grams of methane

Explanation:

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6 0
3 years ago
16.0 grams of molecular oxygen gas is equal to
IceJOKER [234]

One thing to notice in the question is, we are asked about molecular oxygen that has formula O2 not atomic oxygen O.

As we are asked about molecular oxygen, we will answer the question in terms of number of molecules that are present in 16 grams of molecular oxygen.

To get the number of molecules present in 16 grams of O2, we will use the formula:

         No. of molecules = no. of moles x Avogadro's number (NA)-----  eq 1)

As we know:

                        The number of moles = mass/ molar mass of molecule

Here we have been given mass already, 16 grams and the molar mass of O2 is 32 grams.

Putting the values in above formula:

                                                    = 16/32  

                                                     = 0.5 moles

Putting the number of moles and Avogadro's number (6.02 * 10^23) in eq 1

                                No. of molecules = 0.5  x 6.02 * 10^23

                                   =3.01 x 10^23 molecules

or                 301,000,000,000,000,000,000,000 molecules

This means that 16 grams of 3.01 x 10^23 molecules of oxygen.

Hope it helps!

4 0
3 years ago
Read 2 more answers
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