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3 years ago

Which statements describe features that maps and globes share? Check all that apply.

Physics

1 answer:

leonid [27]3 years ago

4 0

Maps and Globes share the following features:

Both are scale Models.

Explanation:

A globe is a scale model of the Earth that presents the most accurate depiction of geographic information such as area, distance, and direction.

A map is a two dimensional representation or a drawing of the earth’s surface, or a part of it, on a flat surface, according to a scale. Thus it is also a scale model.

A globe differs from a map. It is a three dimensional sphere representing the whole Earth.

A map is usually used to represent a specific part of the Earth and is used for Navigation. It has details and symbols. However, a globe can not be used for such details.

A globe can be used to get a broad-level picture of the world.

Keywords: geography, earth, maps, globes

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3 years ago

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A 2800 kg truck moving at 12 m/s to the right hits a stopped 1100 kg car. What is the combined velocity the moment they stick to

leva [86]

Answer:

The combined velocity is 8.61 m/s.

Explanation:

Given that,

The mass of a truck, m = 2800 kg

Initial speed of truck, u = 12 m/s

The mass of a car, m' = 1100 kg

Initial speed of the car, u' = 0

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$m_1v_1+m_2v_2=(m_1+m_2)V\\\\V=\dfrac{m_1v_1+m_2v_2}{(m_1+m_2)}\\\\V=\dfrac{2800\times 12+0}{2800+1100}\\\\V=8.61\ m/s$

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2 years ago

A racecar accelerates from rest at 6.5 m/s2 for 4.1 s. How fast will it be going at the end of that time?

Pie

Answer:

The final velocity of the car is 26.65 m/s.

Explanation:

Given;

acceleration of the racecar, a = 6.5 m/s²

initial velocity of the car, u = 0

time of motion, t = 4.1 s

The final velocity of the car is given by;

v = u + at

where;

v is the final velocity of the car

suvstitute the givens

v = 0 + (6.5)(4.1)

v = 26.65 m/s.

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2 years ago

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viktelen [127]

Answer:

$V_d$ = 1.75 × 10⁻⁴ m/s

Explanation:

Given:

Density of copper, ρ = 8.93 g/cm³

mass, M = 63.5 g/mol

Radius of wire = 0.625 mm

Current, I = 3A

Area of the wire, $A = \frac{\pi d^2}{4}$ = $A = \frac{\pi 0.625^2}{4}$

Now,

The current density, J is given as

$J=\frac{I}{A}=\frac{3}{ \frac{\pi 0.625^2}{4}}$ = 2444619.925 A/mm²

now, the electron density, $n = \frac{\rho}{M}N_A$

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$N_A$ =Avogadro's Number

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the drift velocity, $V_d$

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e = charge on electron = 1.6 × 10⁻¹⁹ C

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3 years ago

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vaieri [72.5K]

Answer:

$1.03$

Explanation:

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Round to three significant digits

$1.03$

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