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Yuri [45]
3 years ago
9

Heat is added to an open pan of water at 100.0°c, vaporizing the water. the expanding steam that results does 43.0 kj of work, a

nd the internal energy of the system increases by 604 kj. how much energy is transferred to the system as heat?
Physics
2 answers:
vampirchik [111]3 years ago
6 0
Heat = change in internal energy + Work done The internal energy of a system = heat added and mechanical work done by the system, i.e. U = Q + W rearranging the formula above, will give us: Q = deltaU + W 
Q = U - W = 604 kJ - 43.0 kJ = 561,000 J would be the answer.
PIT_PIT [208]3 years ago
4 0

Answer:

Heat transferred to the gas is given as

Q = 647 kJ

Explanation:

As per first law of thermodynamics we know that

Q = \Delta U + W

now here we know that

change in internal energy of the gas is

\Delta U = 604 kJ

Also the steam expands so we will have

W = 43 kJ

since volume increases to here work is done by the gas

now from above equation the heat given to the system is

Q = 604 + 43 = 647 kJ

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A 18.0-kg rock is sliding on a rough, horizontal surface at 7.10 m/s and eventually stops due to friction. the coefficient of ki
Bond [772]
A = .3*g = 2.94 m/s² 

<span>t = v/a = 9/2.94 = 3.061 sec </span>

<span>W = E/t = ½mv²/t = ½*40*9²/3.061 = 529.2 watts</span>
4 0
3 years ago
Inez uses hairspray on her hair each morning before going to school. The spray spreads out before reaching her hair partly becau
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The charge on each of the equally charged drops of hairspray willl be 7 × 10 ⁻¹³ C

<h3>What is Columb's law?</h3>

The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

Similar charges repel each other, whereas charges that are opposed attract each other.

Given data;

Electric force,F = 9 × 10 ⁻⁹ N

Distance between charges,d = 7 × 10⁻⁴ m

Chrge,q₁ = q₂ =q C

From Columb's law;

\rm F = K \frac{q_1q_2}{d^2} \\\\ 9 \times 10^{-9}  = 9 \times 10^9 \frac{q^2}{(7 \times 10^{-4})^2} \\\\ q^2 = 4.9 \times 10^{-25} \\\\  q = 7 \times 10^{-13} \ C

Hence the charge on each of the equally charged drops of hairspray willl be 7 × 10 ⁻¹³ C

To learn more about Columb's law refer to the link;

brainly.com/question/1616890

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7 0
2 years ago
Two teams of nine members each engage in tug-of-war. Each of the first team's members has an average mass of 68 kg and exerts an
diamong [38]

Answer:

(a) Acceleration  = 0.1063 m/s^2      (Second team wins)

(b) Tension in rope = 65.106 N

Explanation:

Total mass of first team = 68 * 9 = 612 kg

Total force of first team = 1350 * 9 = 12150 N

Total mass of second team = 73 * 9 = 657 kg

Total force of seconds team = 1365 * 9 = 12285 N

Difference in force = 12285 - 12150 = 135 N   (towards the second team as it has more force)

(a) For acceleration we get:

F = m * a

135 = (mass of both teams) * a

a = 135 / (612 + 657)

acceleration  = 0.1063 m/s^2      (Second team wins)

(b) Since we know the acceleration of the first team (pulling being pulled towards the second team at an acceleration of 0.1063 m/s^2) , we can find out the force required to move them:

Force required for first team = mass of first team * acceleration

Force required = 612 * 0.1063

Force required = 65.106 N

This is the force exerted on the first team through the rope, so the tension in the rope will also be 65.106 N.

7 0
4 years ago
A particle moves according to the equation x = 11t^2, where x is in meters and t is in seconds.
Savatey [412]
We are given the equation:

<span>x = 11t^2
</span>
We use that equation to calculate for the distance traveled.
For (a)

At t=2.20 sec,    
                             x =53.24 meters

At t=2.95 sec,   
                             x =95.73 meters

Velocity = (95.73 meters - 53.24<span> meters) / (2.95 s - 2.20 s )  = 56.65 m/s

</span>For (b)

At t=2.20 sec,    
                             x =53.24 meters

At t=2.40 sec,   
                             x =63.36 meters

Velocity = (63.36 meters - 53.24<span> meters) / (2.40 s - 2.20 s )  = 50.6 m/s</span>
4 0
3 years ago
It is found that the most probable speed of molecules in a gas at equilibrium temperature
kaheart [24]

Answer:

\frac{T_2}{T_1} = 1

Explanation:

The root mean square velocity of the gas at an equilibrium temperature is given by the following formula:

v = \sqrt{\frac{3RT}{M} }

where,

v = root mean square velocity of molecules:

R = Universal Gas Constant

T = Equilibrium Temperature

M = Molecular Mass of the Gas

Therefore,

For T = T₁ :

v = \sqrt{\frac{3RT_1}{M} }

For T = T₂ :

v = \sqrt{\frac{3RT_2}{M} }

Since both speeds are given to be equal. Therefore, comparing both equations, we get:

\sqrt{\frac{3RT_1}{M} }=\sqrt{\frac{3RT_2}{M} }\\\\\frac{T_2}{T_1} = 1

8 0
3 years ago
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