1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
laila [671]
3 years ago
15

The vertical displacement of the wave is measured from the ?

Physics
1 answer:
sergey [27]3 years ago
6 0
The whole question is talking about the amplitude of a wave
that's transverse and wiggling vertically.

Equilibrium to the crest . . . that's the amplitude.

Crest to trough . . . that's double the amplitude.

Trough to trough . . . How did that get in here ?  Yes, that's
                               the wavelength, but it has nothing to do
                               with vertical displacement.

Frequency . . . that's how many complete waves pass a mark
                       on the ground every second.  Doesn't belong here.

Notice that this has to be a transverse wave.  If it's a longitudinal wave,
like sound or a slinky, then it may not have any displacement at all
across the direction it's moving.

It also has to be a vertically 'polarized' wave.  If it's wiggling across
the direction it's traveling BUT it's wiggling side-to-side, then it has
no vertical displacement.  It still has an amplitude, but the amplitude
is all horizontal.
You might be interested in
A 2.0-kg object moving with a velocity of 5.0 m/s in the positive x direction strikes and sticks to a 3.0-kg object moving with
Andrej [43]

Answer:

5.4 J.

Explanation:

Given,

mass of the object, m = 2 Kg

initial speed, u = 5 m/s

mass of another object,m' = 3 kg

initial speed of another orbit,u' = 2 m/s

KE lost after collusion = ?

Final velocity of the system

Using conservation of momentum

m u + m'u' = (m + m') V

2 x 5 + 3 x 2 = ( 2 + 3 )V

16 = 5 V

V = 3.2 m/s

Initial KE = \dfrac{1}{2}mu^2 + \dfrac{1}{2}m'u'^2

              = \dfrac{1}{2}\times 2\times 5^2 + \dfrac{1}{2}\times 3 \times 2^2

              = 31 J

Final KE = \dfrac{1}{2} (m+m')V^2 = \dfrac{1}{2}\times 5 \times 3.2^2 = 25.6 J

Loss in KE = 31 J - 25.6 J = 5.4 J.

4 0
3 years ago
Why isn't the story of Israel not fully accurate?
maksim [4K]

Answer:

wait what do you mean? And why is this in physics?

Is this about the iron dome or something biblical?

Explanation:

5 0
3 years ago
Read 2 more answers
Please help I'll mark brainliest!!!!
madam [21]

This question is based on the fundamental assumption of  vector direction.

A vector is  a physical quantity which has  magnitude as well direction  for its complete specification.

The magnitude of a physical quantity is simply a  numerical number .Hence it can not be negative.

A negative vector is a vector which comes into existence when it is opposite to our assumed direction with respect to any other vector.  For instance, the vector is taken positive if it is along + X axis and negative if it is along - X axis.

As per the first option it is given that a vector is negative if its magnitude is greater than 1. It is not correct as magnitude play no role in it.

The second option tells that the magnitude of the vector is less than 1. Magnitude can not be negative. So this is also wrong.

Third one tells that a vector is negative if its displacement is along north. It does not give any detail information about the negativity of a vector.

In a general sense we assume that vertically downward motion  is negative and vertically upward is positive. In case of a falling object the motion is  vertically downward. So the velocity of that object is negative .

So last   option is  partially  correct  as  the vector can be negative depending on our choice of co-ordinate system.





7 0
3 years ago
Read 2 more answers
to start an avalanche on a mountain slope, an artillery shell is fired with an initial velocity of 290 m/s at 53.0° above the ho
kap26 [50]
So this is easy to calculate when you split the velocity into x and y components. The x component is going to equal cos(53) * 290 and the y component is going to equal sin(53)*290.

The x location therefore is 290*cos(53)*35 = 6108.4m

The y location needs to factor in the downwards acceleration of gravity too, which is 9.81m/s^2. We need the equation dist. = V initial*time + 0.5*acceleration*time^2.

This gives us d=290*sin(53)*35 + (0.5*-9.81*35^2)=2097.5m

So your (x,y) coordinates equals (6108.4, 2097.5)
5 0
3 years ago
How to answer this question?
laila [671]

Answer:

measure the vector diagram first

5 0
2 years ago
Other questions:
  • A 4.30 g bullet moving at 943 m/s strikes a 730 g wooden block at rest on a frictionless surface. The bullet emerges, traveling
    8·1 answer
  • Two charged particles are a distance of 1.62 m from each other. One of the particles has a charge of 7.10 nc, and the other has
    9·1 answer
  • You release a block from the top of a long, slippery inclined plane of length l that makes an angle θ with the horizontal. The m
    7·1 answer
  • What is the couple force​
    6·1 answer
  • What is the soil fabric?
    11·1 answer
  • A new prototype cup has been designed to keep liquids, such as hot coffee or cold annk, near their original temperature for long
    8·1 answer
  • Two identical loudspeakers 2.30 m apart are emitting sound waves into a room where the speed of sound is 340 m/s. Abby is standi
    6·1 answer
  • A truck is traveling at a speed of 50 km/h. What happens when the truck slows down?
    11·1 answer
  • Which type of lever is steep road​
    14·1 answer
  • 1.25 is the closest to 1.04 or not I want to answer please. I think it's true, but I want to prove it scientifically, please.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!