How to answer this question?

If a 4 engine jet accelerates down a runway at 8.7 m/s^2, Suppose now that all 4 engins are operational on the jet from the prev

soldi70 [24.7K]

Answer:

$5.22m/s^2$

Explanation:

One of the first propulsion characteristics given in the example is that all engines are equal.

In this way if we have 4 engines running at the same time, it means that its capacity is 100%.

Under this premise, if 100% is found, the Jet is capable of reaching a speed of 8.7m / s ^ 2.

However, the question is, what would happen if 2.4 "Engines" now work.

To do this then we make a simple equivalence,

If 4 engines is the equivalent of 100%, when would it be 2.4 engines?

$X = \frac{2.4 * 100\%} { 4 }= 60\%$

In this way it would mean that the body could be driven to 60% of its total.

So

$Speed_{Decreased} = 8.7 * 60\% = 5.22 \frac{m}{s^2}$

3 0

3 years ago

A force of 5N produces an acceleration of 8m/s2 on mass m1, and an acceleration of 24m/s2 on a mass m2. What acceleration would

kotykmax [81]

The acceleration that the same force will provide if both masses are tied together is; 6.0 m/s².

<h3>How to find the Acceleration?</h3>

We are given;

Force; F = 5 N

Acceleration of the first mass, a₁ = 8.0 m/s²

Acceleration of the second mass, a₂ = 24 m/s²

Formula for force is;

F = ma

Let us find both masses; m₁ and m₂.

m₁ = F/a₁

m₂ = F/a₂

Thus;

m₁ = 5/8 kg

m₂ = 5/24 kg

Total mass is; m = m₁ + m₂

m = 5/8 + 5/24

m = 15 + 5/24

m = 20/24 kg

Thus, acceleration if they are both tied together is;

a = F/m

a = 5/(20/24)

a = 6.0 m/s².

Read more about Acceleration at; brainly.com/question/605631

#SPJ1

4 0

2 years ago

Ccording to coulomb's law, which pair of charged particles has the lowest potential energy? according to coulomb's law, which pa

Sladkaya [172]

Coulombs law says that the force between any two charges depends on the amount of charges and distance between them. This force is directly proportional to the magnitude of the two charges and inversely proportional to the distance between them.

$F=k\frac{|q_1| |q_2|}{r^2}$

where $q_1\hspace{1mm}and\hspace{1mm}q_2$ are charges, $r$ is the distance between them and k is the coulomb constant.

case 1:

$q_1=-e\\ q_2=+3e\\ r=100pm\\ \Rightarrow F=k\frac{|-e||3e|}{(100pm)^2}=3ke^2\times10^8$

case 2

$q_1=-e\\ q_2=+2e\\ r=100pm\\ \Rightarrow F=k\frac{|-e||2e|}{(100pm)^2}=2ke^2\times10^8$

case 3:

$q_1=-e\\ q_2=+e\\ r=100pm\\ \Rightarrow F=k\frac{|-e||e|}{(200pm)^2}=0.25ke^2\times10^8$

Comparing the 3 cases:

The maximum potential force according to coulombs law is between -1 charge and +3 charge separated by a distance of 100 pm.

3 0

3 years ago

Read 2 more answers

A ____ is a non solid state of matter in which the atoms and molecules are free to move past each other, as in a gas or liquid.

Licemer1 [7]

The answer is GAS. In a gas, the particles are in a completely random motion in any direction. And it is not solid. Hope I helped. Good luck

6 0

3 years ago

Read 2 more answers

an op amp in unity gain configuration (buffer) with slew rate of 5v/us is used to amplify a sinusoidal signal with a frequency o

ZanzabumX [31]

Answer:

The maximum amplitude ( $V_{max}$ ) will be 7.96 V.

Explanation:

We know, for distortion free operation, the slew rate (S) of an OPAMP is written as

$S = 2 \pi f V_{max}$

where ' $f$ ' is the highest frequency signal.

Therefore, from the above equation we can write,

$&&5 \frac{V}{\mu s} = 2 \pi 100 kHz \times V_{max}\\&or,& V_{max} = \frac{5V}{10^{-6} s \times 2 \pi 100 \times 10^{3} Hz}\\&or,& V_{max} = \frac{5}{2 \pi \times 10^{-1}} V = 7.96 V$

3 0

3 years ago