Answer:
average velocity = displacement/time
It might be pull at a force of 100 N. I might be wrong.
Answer:
a) 17.33 V/m
b) 6308 m/s
Explanation:
We start by using equation of motion
s = ut + 1/2at², where
s = 1.2 cm = 0.012 m
u = 0 m/s
t = 3.8*10^-6 s, so that
0.012 = 0 * 3.8*10^-6 + 0.5 * a * (3.8*10^-6)²
0.012 = 0.5 * a * 1.444*10^-11
a = 0.012 / 7.22*10^-12
a = 1.66*10^9 m/s²
If we assume the electric field to be E, and we know that F =qE. Also, from Newton's law, we have F = ma. So that, ma = qE, and E = ma/q, where
E = electric field
m = mass of proton
a = acceleration
q = charge of proton
E = (1.67*10^-27 * 1.66*10^9) / 1.6*10^-19
E = 2.77*10^-18 / 1.6*10^-19
E = 17.33 V/m
Final speed of the proton can be gotten by using
v = u + at
v = 0 + 1.66*10^9 * 3.8*10^-6
v = 6308 m/s
Answer:
a)15077 W
b)20.2185 horse power
Explanation:
P=F*V
F=ma
a=Vf-VS/t
Vf=28m/s
t=5.2
a=28/5.2
a=5.384 m/s²
F=100kg*5.384m/s²
F=538.4 N
P=F*V
P=538.4N*28m/s
P=15077 W=20.2185 horse power
1W=0.00134 Horse power
