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2 years ago

What is the soil fabric?

Physics

1 answer:

inessss [21]2 years ago

5 0

Answer:

The term soil fabric refers to the geometrical arrangement of individual particles in a soil, including the geometrical distribution of pore spaces. Soil fabric may be used to describe the particle arrangement in both cohesive soils such as clays and granular soils such as silts, sands, and gravels.

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Who might be experiencing psychosis?

aleksandrvk [35]

Answer:

Explanation:

I think the answer is D, because of hallucinations

4 0

3 years ago

Un vehiculo se desplaza con movimiento rectilio uniforme. Sabiendo que recorre 90 km en 3 horas. Averiguo la velocidad en m/s.

SashulF [63]

Answer:

Velocidad = 500 m/s

Explanation:

Dados los siguientes datos;

Distancia = 90 km

Tiempo = 3 horas

Conversión;

Por distancia:

1 kilómetro = 1000 metros

90 kilómetros = 90 * 1000 = 90,000 metros

Para el tiempo:

1 hora = 60 segundos

3 horas = 60 * 3 = 180 segundos

Para encontrar la velocidad en m/s;

Matemáticamente, la velocidad viene dada por la ecuación;

$Velocidad = \frac {distancia} {tiempo}$

Sustituyendo en la fórmula, tenemos;

Velocidad = 90000/180

Velocidad = 500 m/s

5 0

2 years ago

suppose a ball had a potential energy of 5 j when you dropped it. What would be its kinetic energy just as it hit the ground. (i

Andru [333]

Since we are ignoring air resistance which is a non-conservative force, the potential energy will be completely converted into kinetic energy, resulting in a final kinetic energy of $5J$ .

4 0

2 years ago

What is the term for the overall change in position?

mart [117]

That's "displacement". It only depends on the beginning and ending locations, and doesn't care about the route between them.

6 0

3 years ago

Read 2 more answers

A police car is traveling north on a straight road at a constant 16.0 m/s. An SUV traveling north at 30.0 m/s passes the police

Nastasia [14]

Answer:

It will take 15.55s for the police car to pass the SUV

Explanation:

We first have to establish that both the police car and the SUV will travel the same distance in the same amount of time. The police car is moving at constant velocity and the SUV is experiencing a deceleration. Thus we will use two distance fromulas (for constant and accelerated motions) with the same variable for t and x:

1. $x=x_{0}+vt$

2. $x=x_{0}+v_{0}t+\frac{at^{2}}{2}$

Since both cars will travel the same distance x, we can equal both formulas and solve for t:

$vt = v_{0}t+\frac{at^2}{2}\\\\ 16\frac{m}{s}t =30\frac{m}{s}t-\frac{1.8\frac{m}{s^{2}} t^{2}}{2}$

We simplify the fraction present and rearrange for our formula so that it equals 0:

$0.9\frac{m}{s^{2}} t^{2}-14\frac{m}{s}t=0 \\\\ t(0.9\frac{m}{s^{2}}t-14\frac{m}{s})=0$

In the very last step we factored a common factor t. There is two possible solutions to the equation at $t=0$ and:

$0.9\frac{m}{s^{2}}t-14\frac{m}{s}=0 \\\\ 0.9\frac{m}{s^{2}}t =14\frac{m}{s} \\\\ t =\frac{14\frac{m}{s}}{0.9\frac{m}{s^{2}}}=15.56s$

What this means is that during the displacement of the police car and SUV, there will be two moments in time where they will be next to each other; at $t=0 s$ (when the SUV passed the police car) and $t=15.56s$ (when the police car catches up to the SUV)

8 0

3 years ago