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2 years ago

8

A new prototype cup has been designed to keep liquids, such as hot coffee or cold annk, near their original temperature for long

periods of time Which statement describes the function of the newly designed
cup

1 answer:

san4es73 [151]2 years ago

4 0

Answer:

hope this was good for u and I believe it would be solid

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The electric potential in a region of space is \[V=350/\sqrt{x ^{2}+y ^{2}}\] where x and y are in meters. what is the strength

VARVARA [1.3K]

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2 years ago

Read 2 more answers

A man pushes on a piano with mass 190 kgkg ; it slides at constant velocity down a ramp that is inclined at 18.0 ∘∘ above the ho

creativ13 [48]

Answer:

The magnitude of applied force,parallel to the incline is 575.38 N and parallel to the floor is 605 N.

Explanation:

Given:

Mass of the piano $(m)$ = 190 kg

Inclined angle $(\theta)$ = 18 degree

Considering gravity, $g$ = 9.8 $ms^-^2$

And

Using, $sin(18) =0.30$ and $cos(18)=0.95$

<em>FBD diagram is attached with all the force acting on the floor and and the inclined. </em>

We have to find the magnitude of forces,when the man pushes it parallel to the incline and to the floor.

a.

When the man pushes it parallel to the incline.

Balancing the forces as $\sum F=0$ .

⇒ $F+mgsin(\theta) =0$

⇒ $F=-mgsin(\theta)$

⇒ Here it is negative as the force is acting downward.

⇒ Plugging the values of mass $(m)$ and angle $(\theta)$ .

⇒ $F=190\times 9.8\times sin(18)$

⇒ $F=575.38$ N

b.

When the force is parallel to the floor.

⇒ $Fcos(\theta)=mgsin(\theta)$

⇒ $F=\frac{mgsin(\theta)}{cos(\theta)}$

⇒ Plugging the values.

⇒ $F=\frac{190\times 9.8\times sin(18)}{cos(18)}$

⇒ $F=605$ N

So,

The magnitude of applied force in inclined direction is 575.38 Newton and parallel to the floor is 605 N.

6 0

2 years ago

Who gains altitude more quickly, a pilot traveling 400 mph and rising at an angle of 30°, or a pilot traveling 300 mph and risin

Basile [38]

The rate of altitude increase is equivalent to the vertical component of the pilot's velocity. Let the first pilot's velocity be A and the second's be B.
Ay = Asin(∅)
Ay = 400sin(30)
Ay = 200 mph

By = Bsin(∅)
By = 300sin(40)
By = 192.8 mph

200 - 192.8 = 7.2 mph
The first pilot gains altitude faster by 7.2 mph than the second pilot.

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2 years ago

The velocity of a car decreases from 28m/s to 20m/s in a time of 4 seconds. what is the average acceleration of the car in this

Olin [163]

The average acceleration of the car in this process is -2 m/s²

<h3>What is Acceleration ?</h3>

Acceleration can be defined as change in velocity per time taken. It is a vector quantity. That is, it has both the magnitude and direction. It is measured in m/s²

Given that a velocity of a car decreases from 28m/s to 20m/s in a time of 4 seconds. Then,

Initial velocity u = 28 m/s

Final velocity v = 20 m/s

Time t = 4 s

Acceleration a = ?

From the definition of acceleration,

a = Δv / t

a = ( 20 - 28 ) / 4

a = -8 / 4

a = - 2 m/s²

Therefore, the average acceleration of the car in this process is -2 m/s² which mean that the car is decelerating.

Learn more about Deceleration here: brainly.com/question/25311290

#SPJ1

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1 year ago