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3 years ago

8

A new prototype cup has been designed to keep liquids, such as hot coffee or cold annk, near their original temperature for long

periods of time Which statement describes the function of the newly designed
cup

1 answer:

san4es73 [151]3 years ago

4 0

Answer:

hope this was good for u and I believe it would be solid

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A feverish student weighing 75,000 grams was immersed in 400,000 g of water at 4.0°C to try to reduce the fever. The student's b

schepotkina [342]

Heat lost = (75000)(3.77)(3) = 848250 J = heat gained by water

848250 = 400000(4.814)(T)
T = 0.507 C
4 + 0.507 = 4.507 C

3 0

3 years ago

A block of mass 3.6 kg, sliding on a horizontal plane, is released with a velocity of 1.7 m/s. The block slides and stops at a d

pentagon [3]

Answer:

The block would have slid <u>12.6 m</u> if its initial velocity were increased by a factor of 2.8.

Explanation:

Given:

Mass of the block (m) = 3.6 kg

Initial velocity (u) = 1.7 m/s

Final velocity (v) = 0 m/s

Displacement (S) = 1.6 m

First we will find the acceleration of the block.

Using the equation of motion, we have:

$v^2=u^2+2aS\\\\a=\dfrac{v^2-u^2}{2S}$

Now, plug in the given values and solve for 'a'. This gives,

$a=\frac{0-1.7^2}{2\times 1.6}\\\\a=\frac{-2.89}{3.2}=0.903\ m/s^2$

The acceleration is negative as it is resisting the motion.

Now, the initial velocity is increased by a factor of 2.8. So,

New initial velocity = 2.8 × 1.7 = 4.76 m/s

Again using the same equation of motion and expressing the result in terms of 'S'. This gives,

$v^2=u^2+2aS\\\\S=\dfrac{v^2-u^2}{2a}$

Now, plug in the given values and solve for 'S'. This gives,

$S=\frac{0-4.76^2}{2\times -0.903}\\\\S=\frac{-22.6576}{-1.806}=12.6\ m$

Therefore, the block would have slid 12.6 m if its initial velocity were increased by a factor of 2.8

6 0

3 years ago

An EM wave has a wave length of 956 m, What type of electromagnetic waves is this wave

Assoli18 [71]

The electromagnetic spectrum allows finding the result for the question of type of electromagnetic wave has a wavelength of 956 nm

The wave is in the near infrared range.

The electromagnetic wave is an oscillation of electric fields and magnets field that sustain each other, this wave time has the characteristics that it can travel without a material medium, for which they are of extreme importance.

Consequently the spectrum of electromagnetic waves to each part has been given a different name second to its use, for example

Range Name

Ultraviolet light 200 to 400 nm

Visible light 400 to 700 nm

Infrared light (heat ) 700 nm to 1 mm

The latter is subdivided into:

Near infrared 700 nm to 1000 nm (1 μm)

Medium infrared 1 μm to 30 μm

Far infrared 50 μm to 1000 μm

It indicates that the wavelength of the measured radiation is 956 nm, therefore it is in the near infrared range.

Learn more about the electromagnetism spectrum here: brainly.com/question/23727978

6 0

2 years ago

gayle cooks a roast in her microwave oven. the klystron tube in the oven emits photons whose energy is 1.20 x 10^-3 ev. what are

AveGali [126]

Answer:

$\lambda=1.03\times 10^{-3}\ m$

Explanation:

Given that,

The energy of the microwave oven is $1.2\times 10^{-3}\ eV$ .

We need to find the wavelength of these photons.

$1.2\times 10^{-3}\ eV=1.2\times 10^{-3}\times 1.6\times 10^{-19}\\\\=1.92\times 10^{-22}\ J$

The energy of a wave is given by :

$E=\dfrac{hc}{\lambda}\\\\\lambda=\dfrac{hc}{E}$

Put all the values,

$\lambda=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{1.92\times 10^{-22}}\\\\\lambda=1.03\times 10^{-3}\ m$

So, the wavelength of these photon is $1.03\times 10^{-3}\ m$ .

7 0

3 years ago

What are the two groups of planets based on composition?

iris [78.8K]

OK so yeah the mercury Venus Earth and Mars a rocky planets and Jupiter Saturn Uranus and Neptune our gaseous planets so I think that’s your answer correct me if I’m wrong:D

7 0

2 years ago