Answer:
B). the atom is made up of smaller particles
Answer:
Impulse = 10.36 kg m/s
average force = 172.667 N
Explanation:
given data
mass = 0.280 kg
speed = 15.0 m/s
speed = 22.0 m/s
to find out
impulse and magnitude of the average force
solution
we know that Impulse is change in momentum that is
initial momentum = mass × speed ..........1
initial momentum = 0.28 × (15)
initial momentum = 4.2 kg m/s
Final momentum = mass × speed ..........2
Final momentum = 0.28 × (-22)
Final momentum = -6.16 kg m/s
so now we get Impulse that is
Impulse = 4.2 - (-6.16)
Impulse = 10.36 kg m/s
and
average force will be
average force = impulse ÷ time
average force = 
average force = 172.667 N
Answer:
The answer is
<h2>4 hrs</h2>
Explanation:
To find the time taken we use the formula

where
d is the distance covered
v is the velocity
t is the time
From the question
d = 1200 miles
v = 300 mi/hr
We have

We have the final answer as
<h3>4 hrs</h3>
Hope this helps you
Answer:
Q₂ = (9.83 × 10⁻⁹) C = +9.83 nC
Explanation:
The force of attraction/repulsion between the two charges is equal to the force of gravity on the charge 2.
The force of gravity on the charge two = mg
= 6.5 μg × 9.8 m/s² = (6.37 × 10⁻⁵) N
Since the gravity force is directed downwards, the force on charge 2 due to charge 1 has to be directed upwards, hence it is a force of repulsion.
The magnitude of the force between the two charges is given according to the Coulomb's law.
F = kQ₁Q₂/r²
k = Coulomb's constant = (9.0 × 10⁹) Nm²/C²
Q₁ = 45 nC = (45 × 10⁻⁹) C
Q₂ = ?
r = 25 cm = 0.25 m
F = (6.37 × 10⁻⁵) N
(6.37 × 10⁻⁵) = [(9.0 × 10⁹) × (45 × 10⁻⁹) × Q₂] ÷ 0.25²
Q₂ = 0.00000000983 C = (9.83 × 10⁻⁹) C = 9.83 nC
Hope this Helps!!!