Answer:
Pitch. The sound an article makes changes relying upon how quick it is vibrating. At the point when an item vibrates rapidly, sharp sounds are heard. Low-pitched sounds come from things that vibrate all the more gradually.
Explanation:
Answer:
It's weight would decrease over time.
Explanation:
The cold coke is going to stabilise in the room temperature. This causes the coke to heat up to room temperature. When the coke heats up, some molecules acquire enough kinetic energy that the evaporate. The evaporation of the molecules causes a decrease in weight.
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Answer:
2 in front of water and 1 in front of oxygen
Explanation:
This question is describing balancing a chemical reaction. A balanced chemical reaction has the same number of atoms of each elements on both the reactant and product side. According to the question, the reactants contains 4 atoms of oxygen. The reactants give rise to water (H20) and O2 in the products side.
This reaction is most likely the decomposition of hydrogen peroxide (H2O2) as follows:
H2O2 (l) ----> H2O (l) + O2(g)
Based on the description, H2O2 will be 2H2O2 as it is said to contain four atoms of oxygen. This means that, in order to have a balanced equation, we must place coefficient 2 in front of water and coefficient 1 in front of oxygen. That is;
2H2O2 (l) ----> 2H2O (l) + O2(g)
Answer:
(C) 40m/s
Explanation:
Given;
spring constant of the catapult, k = 10,000 N/m
compression of the spring, x = 0.5 m
mass of the launched object, m = 1.56 kg
Apply the principle of conservation of energy;
Elastic potential energy of the catapult = kinetic energy of the target launched.
¹/₂kx² = ¹/₂mv²
where;
v is the target's velocity as it leaves the catapult
kx² = mv²
v² = kx² / m
v² = (10000 x 0.5²) / (1.56)
v² = 1602.56
v = √1602.56
v = 40.03 m/s
v ≅ 40 m/s
Therefore, the target's velocity as it leaves the spring is 40 m/s
Answer:
Explanation:
The resistance of a piece of wire is given by
where
is the resistivity of the material
L is the length of the wire
A is the cross-sectional area
In this problem, we have
L = 7.0 m
The diameter of the wire is 0.14 cm, so the radius is 0.07 cm, therefore the cross sectional area is
Therefore, the resistance is
