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iragen [17]
3 years ago
14

Noble gases, such as argon and neon, are known for being extremely non-reactive. Neon and argon are non-reactive because they A.

have six electrons in their outer shell. B. have eight electrons in their outer shell. C. have ten electrons in their outer shell. D. have 18 electrons in their outer shell.
Physics
2 answers:
Nata [24]3 years ago
4 0

Answer: B. Have eight electrons in their outer shell.

Explanation:

Noble gases are known for their unreactive nature due to the presence of complete outermost electron. They possess eight electrons in their outermost shell (octet rule). Being unreactive means that they cannot share any of their outermost electron to any other atoms since they are completely filled up (stable).

Taking sodium(2 8 1) which is reactive as an example, its reactivity is due to the presence of a lone pair of electron in its outermost shell which it can easily share to other atom with incomplete outermost electron like chlorine (2 8 7).

Greeley [361]3 years ago
3 0
B. have eight electrons in their outer shell
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A diode vacuum tube consists of a cathode and an anode spaced 5-mm apart. If 300 V are applied across the plates. What is the ve
MAXImum [283]

Answer:

Explanation:

There is electric field between the plates whose value is given by the following expression

electric field E =  V /d where V is potential between the plates and d is distance between them

E = 300 / 5 x 10⁻³

=  60 x 10³ N/c

Force on electron = q E where q is charge on the electron

F = 1.6 X 10⁻¹⁹ X 60 X 10³ = 96 X 10⁻¹⁶ N.

Acceleration a = force / mass

a = 96 x 10⁻¹⁶/ mass  = 96 x 10⁻¹⁶ / 9.1 x 10⁻³¹

= 10.55 x 10¹⁵ m / s²

For midway , distance travelled

s =  2.5 x 10⁻³ m

s      =  1\2 a t²

t = \sqrt{\frac{2s}{a\\ } }

= \sqrt{\frac{2\times2.5\times10^{-3}}{ 10.55\times10^{15}}

t = .474 x 10⁻¹⁸ s

For striking the plate time is calculated as follows

t = [tex]\sqrt{\frac{2\times5\times10^{-3}}{ 10.55\times10^{15}}[/tex]

t = 0.67 x 10⁻¹⁸ s

3 0
3 years ago
Assuming the input of energy continues for another 2.5 seconds, where will the particle be?
VladimirAG [237]
Well i had the same question on my test, and when the graph in 2.5 seconds goes up from the equilibrium it reaches a positive maximum, so that would be your answer. 

b. positive maximum 
3 0
3 years ago
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