Which two factors affect the size of the gravitational field?

A car travels along a straight line at a constant speed of 53.0 mi/h for a distance d and then another distance d in the same di

Shalnov [3]

A distance of d is covered with 53 mile/hr initially. Time taken to cover this distance t1 = d/53 hour Next distance of d is covered with x mile hours. Time taken to cover this distance t2 = d/x hours. We have average speed = 26.5 mile / hour

= Total distance traveled/ total time taken

= $\frac{2d}{\frac{d}{53}+\frac{d}{x}} = \frac{2}{\frac{1}{53}+\frac{1}{x} } = \frac{106x}{x+53}$

$26.5 = \frac{106x}{x+53} \\ \\ 79.5 x = 1404.5\\ \\ x = 17.67 miles/hour$

5 0

3 years ago

A ball is thrown straight up with a speed of 30 m/s, and air resistance is negligible. How long does it take the ball to reach t

PolarNik [594]

Answer:

3 seconds

Explanation:

Applying,

v = u±gt................ Equation 1

Where v = final velocity, u = initial velocity, t = time, g = acceleration due to gravity.

From the question,

Given: v = 0 m/s ( at the maximum height), u = 30 m/s

Constant: g = -10 m/s

Substitute these values into equation 1

0 = 30-10t

10t = 30

t = 30/10

t = 3 seconds

6 0

2 years ago

A 600 kg car is at test and then accelerated to 5m/s , what is its original kinetic energy

ycow [4]

Answer:

0 J

Explanation:

Kinetic energy is defined as:

KE = 1/2 m v²

where m is mass and v is velocity.

The car starts at rest, so it has zero velocity. Therefore, its initial kinetic energy is 0 J.

3 0

3 years ago

250 W 12 km/h<br>4. Convert yoor answer from 3 to meters per second.

taurus [48]

Answer: 3.33 m/s

Explanation:

Assuming the questions is to convert 12 km/h to meter per second (m/s), let's begin:

In order to make the conversion, we have to know the following:

$1 km=1000 m$

And:

$1 h=3600 s$

Keeping this in mind, we can make the conversion:

$12 \frac{km}{h} \frac{1000 m}{1 km} \frac{1h}{3600 s}$

Then:

$12 \frac{km}{h}= 3.33 \frac{m}{s}$

5 0

3 years ago

Heights of men on a baseball team have a bell-shaped distribution with a mean of 166 cm 166 cm and a standard deviation of 5 cm

kaheart [24]

Answer:

95 %

99.7 %

Explanation:

$\mu$ = 166 cm = Mean

$\sigma$ = 5 cm = Standard deviation

a) 156 cm and 176 cm

$166-5\times 2=156$

$166+5\times 2=176$

From the empirical rule 95% of all values are within 2 standard deviation of the mean, so about 95% of men are between 156 cm and 176 cm.

b) 151 cm and 181 cm

$166-5\times 3 =151$

$166+5\times 3=181$

The empirical rule tells us that about 99.7% of all values are within 3 standard deviations of the mean, so about 99.7% of men are between 151 cm and 181 cm.

3 0

3 years ago