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o-na [289]
3 years ago
10

There were two containers of oil. There was twice as much oil in the second container as in the first one. After using 13 liters

of oil from the first container and 7 liters from the second one, the second container still had 3 times more oil than the first one. How many liters of oil in total were in both containers originally?
PleASE HELP
Mathematics
1 answer:
Natasha2012 [34]3 years ago
4 0

Answer:

There are 96 liters of oil in both containers originally

Step-by-step explanation:

* Lets change the story problem to mathematics equation

- Let the first container had A liters of oil and the second container

 had B liters of oil

- The quantity of oil B in the second container is twice the quantity

  of oil in A in the first container

∴ B = 2A ⇒ (1)

- After using 13 liters from the quantity of oil A in the first container,

 the container had (A - 13) liters

- After using 7 liters from the quantity of oil B in the second container,

 the container had (B - 7) liters

-  After that the quantity of oil in the second container is 3 times

 more oil than the first one

∴ B - 7 = 3(A - 13) ⇒ simplify

∴ B - 7 = 3A - 39 ⇒ add 7 and subtract 3A from both sides

∴ B - 3A = -39 + 7

∴ B - 3A = -32 ⇒ (2)

- Substitute the value of B from (1) into (2)

∴ 2A - 3A = -32

∴ -A = -32 ⇒ × -1

∴ A = 32 liters

- Find the value of B by substitute value of A in (1)

∴ B = 2(32) = 64 liters

- Now find the total liters of oil in both containers

∴ A + B = 32 + 64 = 96 liters

* There are 96 liters of oil in both containers originally

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chosing another point (x,y) we have

y-4/x-8= -2/5

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A line passes through the point (5,-11) and has a slope of -2 Find an equation of this line.
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Now find y intercept (b)

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If f(x) = 5x + 40, what is f(x) when x = -5?
Makovka662 [10]

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f(-5) = 15

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When calculating the area of a circle for diameter and radius is our answer going to be(example) 21 cm square???
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3 years ago
The heights of young women aged 20 to 29 follow approximately the N(64, 2.7) distribution. Young men the same age have heights d
murzikaleks [220]

Answer: 10.703%

Step-by-step explanation:

Let minimum height of the tallest 25% of young women be M.

Let Q be the random variable which denotes the height of young women.

Therefore, Q – N(64,2.70)

Now, P(Q˂M) = 1-0.25

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I.e. ф-1 [(M-64)/2.7] = 0.75 i.e. (M-64)/2.7 = ф-1 (0.75) = 0.675 i.e. M = 65.8198 inches

Let R be the random variable denoting the height of young men

Therefore, R – N (69.3, 2.8)

i.e. (R-69.3)/2.8 – N(0,1)

therefore the probability required = P(R ˂65.8198) = P[(R-69.3)/2.8 ˂ (65.8198 – 69.3)/2.8]

this gives P[(R-69.3)/2.8 ˂] = ф (-1.2429) = 0.107033

From this, the percentage of young men shorter than the shortest amongst the tallest 25% of young women is 10.703%

4 0
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