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11111nata11111 [884]
3 years ago
12

What is the frequency of an x-ray with wavelength 0.15 nm ? assume that the wave travels in free space?

Physics
1 answer:
Roman55 [17]3 years ago
7 0
Let's convert first the wavelength into meters:
\lambda = 0.15 nm = 0.15 \cdot 10^{-9}m
Then, we know that the wavelength is related to the frequency by the following equation:
f =  \frac{c}{\lambda}
Where c=3 \cdot 10^8 m/s is the speed of light in free space. Therefore, putting in the numbers, we find the frequency f:
f= \frac{3 \cdot 10^8 m/s}{0.15 \cdot 10^{-9}m}=2 \cdot 10^{18}Hz
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The unit of energy is a derived quantity. why​
Lubov Fominskaja [6]

Answer:

Energy is the tendency to do work.

Explanation:

Energy unit is Joule

1 Joule means 1 kgm²/s²

Energy =Kinertic energy

=1/2 mv²

unit= kgm²/s²

So energy unit is derived unit.

7 0
3 years ago
draw conclusions on the relative densities of liquid water and ice . which is more dense and how do you know . what non-mathemat
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Well ice would be less dense, as water freezes it expands which would reduce density and you can tell just by putting ice cubes in water
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4 years ago
. A long 10-cm-diameter steam pipe whose external surface temperature is 110oC passes through some open area that is not protect
Nata [24]

Answer:

Nu = 30.311

Explanation:

Let consider that pipe is a horizontal cylinder. The Nusselt number is equal to:

Nu = \left\{0.6+\frac{0.387\cdot Ra_{D}^{\frac{1}{6} }}{[1+\left(\frac{0.559}{Pr}  \right)^{\frac{9}{16}} ]^{\frac{8}{27} }}  \right\}^{2}, for Ra_{D} \le 10^{12}.

Where Ra_{D} is the Rayleigh number associated with the cylinder.

The Rayleigh number is:

Ra_{D} = \frac{g\cdot \beta\cdot (T_{pipe}-T_{air})\cdot D^{3}}{\nu^{2}}\cdot Pr

By assuming that air behaves ideally, the coefficient of volume expansion is:

\beta = \frac{1}{T}

\beta = \frac{1}{283.15\,K}

\beta = 3.532\times 10^{-3}\,\frac{1}{K}

The cinematic and dynamic viscosities, thermal conductivity and isobaric specific heat of air at 10 °C and 1 atm are:

\nu = 1.426\times 10^{-5}\,\frac{m^{2}}{s}

\mu = 1.778\times 10^{-5}\,\frac{kg}{m\cdot s}

k = 0.02439\,\frac{W}{m\cdot ^{\textdegree}C}

c_{p} = 1006\,\frac{J}{kg\cdot ^{\textdegree}C}

The Prandtl number is:

Pr = \frac{\mu\cdot c_{p}}{k}

Pr = \frac{(1.778\times 10^{-5}\,\frac{kg}{m\cdot s} )\cdot (1006\,\frac{J}{kg\cdot ^{\textdegree}C} )}{0.02439\,\frac{W}{m\cdot ^{\textdegree}C} }

Pr = 0.733

Likewise, the Rayleigh number is:

Ra_{D} = \frac{(9.807\,\frac{m}{s^{2}} )\cdot (3.532\times 10^{-3}\,\frac{1}{K} )\cdot (110^{\textdegree}C-10^{\textdegree}C)\cdot (0.1\,m)^{3}}{(1.426\times 10^{-5}\,\frac{m^{2}}{s})^{2} }\cdot (0.733)

Ra_{D} = 12.486\times 10^{6}

Finally, the Nusselt number is:

Nu = \left\{0.6+\frac{0.387\cdot (12.486\times 10^{6})^{\frac{1}{6} }}{\left[1 + \left(\frac{0.559}{0.733}\right)^{\frac{9}{16} }\right]^{\frac{8}{27} }}  \right\}^{2}

Nu = 30.311

8 0
3 years ago
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Sayuri is a new, eight-year-old Japanese girl in the neighborhood. When Martha, her teacher at school, interacted with Sayuri, s
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I think the answer to this question is A because she acts differently from the other children
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The design phase in which a building project's basic functional requirements are first laid out (square footage, utility and equ
VikaD [51]

Answer:

e. design programming

Explanation:

The planning techniques are responsible for structuring the tasks to be performed within the project, defining the duration and the order of execution of the same, while the programming techniques try to organize the activities so that the logical temporal relationships between them, determining the calendar or the moments of time in which each one must be realized. The programming must be consistent with the objectives pursued and respect existing restrictions (resources, costs, workloads).

The programming therefore consists in setting, in an approximate way, the moments of beginning and termination of each activity. Some activities may have slack and others are critical activities (fixed over time).

STEPS:

Build a time diagram (moments of beginning and slack of activities).

Establish the times of each activity.

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4 years ago
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