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MatroZZZ [7]
3 years ago
7

The design phase in which a building project's basic functional requirements are first laid out (square footage, utility and equ

ipment needs, and so on) is called the __________ phase.
a. contract
b. documents
c. design/development
d. schematic
e. design programming
Physics
1 answer:
VikaD [51]3 years ago
7 0

Answer:

e. design programming

Explanation:

The planning techniques are responsible for structuring the tasks to be performed within the project, defining the duration and the order of execution of the same, while the programming techniques try to organize the activities so that the logical temporal relationships between them, determining the calendar or the moments of time in which each one must be realized. The programming must be consistent with the objectives pursued and respect existing restrictions (resources, costs, workloads).

The programming therefore consists in setting, in an approximate way, the moments of beginning and termination of each activity. Some activities may have slack and others are critical activities (fixed over time).

STEPS:

Build a time diagram (moments of beginning and slack of activities).

Establish the times of each activity.

Analyze project costs and adjust clearances (minimum cost project).

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Answer:

the answer is ....angle of reflection

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Why is the study of black holes important?
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7 0
2 years ago
A box sits on the back of a flatbed truck. If the coefficient of static friction between the box and the truck bed is μs = 0.400
slava [35]

Answer:

28,699m

Explanation:

The force to make the box move should be <u>μs.N=μs.m.g=m.</u><u>|</u><u>a</u><u>|</u>

then,

|a|=μs.g

Being

μs coefficient of static friction,

N the force made by the truck on the box caused by the gravity force,

m the mass,

g the acceleration of gravity

and a the acceleration of the truck.

x = v \times t  +  \frac{1}{2} \times a \times   {t}^{2}

as the truck is stopping, the acceleration is negative. then,

x = v \times t  -  \frac{1}{2} \times  |a| \times   {t}^{2}

|a|  = v  \div  t \\ t = v \div   |a|

x = v \times (v \div   |a| ) -  \frac{1}{2} \times  |a| \times   {(v \div   |a|)}^{2}

x = v \times (v \div  μs.g ) -  \frac{1}{2} \times  |a| \times   {(v \div   μs.g)}^{2}

x =   \frac{{v}^{2}}{μs \times g} -  \frac{1}{2} \times  \frac{{v}^{2}}{μs \times g} \\ x = \frac{1}{2} \times  \frac{{v}^{2}}{μs \times g} \\ x = 0.5 \times  \frac{{(15m/s) }^{2} }{0.4 \times 9.8m/ {s}^{2} }  = 28.699m

28,699m

7 0
3 years ago
List an example of each of the four classes polymers that living things make and use
slamgirl [31]


The four classes of polymers are:

1. Nucleic acids.  Examples are DNA and RNA

2. Protein. Examples are enzymes and hemoglobin

3. Carbohydrates. Examples as starch and glycogen

4. Lipids. Examples are triglycerides and phospholipids

The building blocks of nucleic acids are called bases and there are four types known as Guanine, Adenine, Thymine and Cytosine.

The building blocks of carbohydrates are glucose molecules.

The building blocks of protein are amino acids.

The building blocks of lipids are a combination of fatty acids and glycerol.

6 0
3 years ago
A bike with 15cm diameter wheels accelerates uniformly from rest to a speed of 7.1m/s over a distance of 35.4m. Determine the an
Finger [1]

Answer:

9.47 rad/s^2

Explanation:

Diameter = 15 cm, radius, r = diameter / 2 = 7.5 cm = 0.075 m, u = 0, v = 7.1 m/s,

s = 35.4 m

let a be the linear acceleration.

Use III equation of motion.

v^2 = u^2 + 2 a s

7.1 x 7.1 = 0 + 2 x a x 35.4

a = 0.71 m/s^2

Now the relation between linear acceleration and angular acceleration is

a = r x α

where,  α is angular acceleration

α = 0.71 / 0.075 = 9.47 rad/s^2

8 0
3 years ago
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