Answer:
Energy = 7.83 x 10⁻¹⁹ J
Energy = 6.63 x 10⁻¹⁹ J
Explanation:
The energy of a photon in terms of wavelength can be calculated by the following formula:
where,
h = Plank's Constant = 6.63 x 10⁻³⁴ Js
c = speed of light = 3 x 10⁸ m/s
λ = wavelength of light
Now, for λ = 254 nm = 2.54 x 10⁻⁷ m:
<u>Energy = 7.83 x 10⁻¹⁹ J</u>
<u></u>
Now, for λ = 300 nm = 3 x 10⁻⁷ m:
<u>Energy = 6.63 x 10⁻¹⁹ J</u>
Explanation:
In a vacuum (no air resistance), it doesn't. All falling objects, regardless of mass, accelerate at the same rate.
However, when air resistance is taken into account, heavier objects indeed fall faster than lighter objects, provided they have the same shape and size. For example, a lead ball falls faster than a styrofoam ball.
To understand why, first look at what factors affect air resistance:
D = ½ρv²CA
where ρ is air density,
v is velocity,
C is drag coefficient,
and A is cross sectional area.
As falling objects accelerate, they eventually reach a maximum velocity where air resistance equals weight. This is called terminal velocity.
D = W
½ρv²CA = mg
v = √(2mg/(ρCA))
If we increase m while holding everything else constant, v increases. So two objects with the same size and shape but different masses will have different terminal velocities, with the heavier object falling faster.
Answer:
340 seconds = 5.667 minutes
Explanation:
As we know, S = v t or t = S / v (S = 51 x 10^9 m and v = 3 x 10^8 ms^-1)
So, t = 51 x 10^9 / 3 x 10^8 = 17 x 10^1 = 170 s
For a RTT estimation, the time span will be doubled of one way propagation for transmission and receive delay.
The over all round trip time will be = 170 x 2 = 340 seconds = 5.667 minutes
Answer:
a) The uniform velocity travelled by the car is 10 meters per second.
(Point b has been erased by the user)
c) The distance travelled by the car with uniform velocity is 100 meters.
Explanation:
a) Calculate the uniform velocity travelled by the car:
The uniform velocity is the final velocity (
), in meters per second, of the the uniform accelerated stage:
(1)
Where:
- Initial velocity, in meters per second.
- Acceleration, in meters per square second.
- Time, in seconds.
If we know that 
, 
and 
, then the uniform velocity is:
The uniform velocity travelled by the car is 10 meters per second.
(Point b has been erased by the user)
c) The distance travelled by the car (
), in meters, with uniform velocity is calculated by the following kinematic expression:
(2)
If we know that and 
, then the distance travelled is:
The distance travelled by the car with uniform velocity is 100 meters.
