Number of O atoms : 24
<h3>Further explanation</h3>
Given
C₆H₁₂O₆ compound
Required
Number of atoms
Solution
A molecular formula shows the number of atomic elements in compound.
The empirical formula is the smallest comparison of the atoms
Glucose-C₆H₁₂O₆ is composed of 3 elements, namely C, H, and O.
The number of atoms in a compound can usually be seen from the subscript number after the atom and the reaction coefficient shows the number of molecules
So number of O atoms :
= 4 x 6 = 24 atoms
Answer : The final number of moles of gas that withdrawn from the tank to lower the pressure of the gas must be, 0.301 mol.
Explanation :
As we know that:

At constant volume and temperature of gas, the pressure will be directly proportional to the number of moles of gas.
The relation between pressure and number of moles of gas will be:

where,
= initial pressure of gas = 24.5 atm
= final pressure of gas = 5.30 atm
= initial number of moles of gas = 1.40 moles
= final number of moles of gas = ?
Now put all the given values in the above expression, we get:


Therefore, the final number of moles of gas that withdrawn from the tank to lower the pressure of the gas must be, 0.301 mol.